When x = 1, y = 1 + 4 = 5
When x = 3, y = 3 + 4 = 7
When x = 5, y = 5 + 4 = 9
When x = 7, y = 7 + 4 = 11
Therefore, the correct answer is option D.
Answer:
B and C
(I'm not sure if b and e are supposed to be the same though) if they are then, b, c, and e
D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)
Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1
I has to be C
Good luck have a good day
Answer: second one is the answer
Hope this helps, im sure of my answer
