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olga_2 [115]
3 years ago
9

Define a variable write an equation and solve the problem. the width of a rectangle is 3 meters more than one-fourth its length.

the perimeter is 10 meters more than twice its length. find the length and width
Mathematics
1 answer:
sweet [91]3 years ago
4 0

Let's assume

length of rectangle is L

width of rectangle is W

the width of a rectangle is 3 meters more than one-fourth its length

so,

W=3+\frac{1}{4} L

the perimeter is 10 meters more than twice its length

we know that

perimeter =2(L+W)

so, we get

2(L+W)=10+2L

now, we can simplify it

2L+2W=10+2L

subtract both sides by 2L

2L+2W-2L=10+2L-2L

2W=10

W=5

now, we can find L

5=3+\frac{1}{4} L

subtract both sides 3

5-3=3-3+\frac{1}{4} L

2=\frac{1}{4} L

multiply both sides by 4

4*2=4*\frac{1}{4} L

L=8

so,

length of rectangle is 8 meter

width of rectangle is 5 meter ............Answer

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95% confidence interval for the population standard deviation of the lifetimes of the batteries produced by the manufacturer.

(x^{-} - t_{\frac{\alpha }{2}  } \frac{S}{\sqrt{n} } , x^{-} +t_{\frac{\alpha }{2}  } \frac{S}{\sqrt{n} } )

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