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Eva8 [605]
3 years ago
7

Breakfast eaten and the slim camp-outfit lashed to the sled, the men turned their backs on the cheery fire and launched out into

the darkness. At once began to rise the cries that were fiercely sad—cries that called through the darkness and cold to one another and answered back. Conversation ceased. Daylight came at nine o'clock. At midday the sky to the south warmed to rose-colour, and marked where the bulge of the earth intervened between the meridian sun and the northern world. But the rose-colour swiftly faded. The grey light of day that remained lasted until three o'clock, when it, too, faded, and the pall of the Arctic night descended upon the lone and silent land.
As darkness came on, the hunting-cries to right and left and rear drew closer—so close that more than once they sent surges of fear through the toiling dogs, throwing them into short-lived panics.

At the conclusion of one such panic, when he and Henry had got the dogs back in the traces, Bill said:

"I wisht they'd strike game somewheres, an' go away an' leave us alone."

"They do get on the nerves horrible," Henry sympathized.

They spoke no more until camp was made.

Read this line from the story:
As darkness came on, the hunting-cries to right and left and rear drew closer, ...

What is the purpose of this sentence in the story? (5 points)

It implies a mood of utter despair.
It implies a near tragic event.
It creates a feeling of being trapped.
It creates a sense of action. I AM GIVING 50 POINTS!!!!!!!!!!!!!!!!!
Mathematics
1 answer:
Olenka [21]3 years ago
8 0

Answer:

A

Step-by-step explanation:

The problem with this kind of question is that the author tells you what you should see in that sentence. The dogs experienced fear. Any other answer you suggest is not what the author means. So you are guessing. It is adding to the notion that the arctic is not a friendly place and you cannot go sunbathing in and be comfortable in the middle of winter.

A is as good an answer as you are likely to get, but I don't think it's right.

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The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 10
serious [3.7K]

Answer:

The rate of change of the height of the box at which is decreasing is \frac{5000}{130321} centimeters per second.

Step-by-step explanation:

From Geometry the volume of a rectangular box (V), measured in cubic centimeters, with a square base is modelled by the following formula:

V = A_{b}\cdot h (Eq. 1)

Where:

A_{b} - Area of the base, measured in square centimeters.

h - Height of the box, measured in centimeters.

The height of the box is cleared within the formula:

h = \frac{V}{A_{b}}

If we know that V = 500\,cm^{3} and A_{b} = 361\,cm^{2}, then the current height of the box is:

h = \frac{500\,cm^{3}}{361\,cm^{2}}

h = \frac{500}{361}\,cm

The rate of change of volume in time (\frac{dV}{dt}), measured in cubic centimeters per second, is derived from (Eq. 1):

\frac{dV}{dt} = \frac{dA_{b}}{dt}\cdot h + A_{b}\cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA_{b}}{dt} - Rate of change of the area of the base in time, measured in square centimeters per second.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per second.

If we get that \frac{dV}{dt} = 0\,\frac{cm^{3}}{s}, \frac{dA_{s}}{dt} = 10\,\frac{cm^{2}}{s}, h = \frac{500}{361}\,cm and A_{b} = 361\,cm^{2}, then the equation above is reduced into this form:

0\,\frac{cm^{3}}{s} = \left(10\,\frac{cm^{2}}{s} \right)\cdot \left(\frac{500}{361}\,cm \right)+(361\,cm^{2})\cdot \frac{dh}{dt}

Then, the rate of change of the height of the box at which is decreasing is:

\frac{dh}{dt} = -\frac{5000}{130321}\,\frac{cm}{s}

The rate of change of the height of the box at which is decreasing is \frac{5000}{130321} centimeters per second.

5 0
3 years ago
Please help!! i’ll mark u brainliest !! <333333333333
Viefleur [7K]
Go to size on the bottom count 8 numbers, go up 5, mark a point. do the rest for all the numbers in the box!
6 0
2 years ago
Jasmine has taken an online boating course safety course and now completing her end-of-course exam . As she answers each questio
melomori [17]

Answer:

80

Step-by-step explanation:

20 percent is 16 questions

then 100/20=5

5 times 16 is 80

6 0
3 years ago
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Papessa [141]
This would be the answer c
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2 years ago
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Circle O has radius of 24 units. Arc XY located on the circle has a central angle of 75 degrees. What is the area of the associa
elena-s [515]

The area of the associated sector is: 120π

<h3>What is a sector?</h3>

A sector is the portion of the area of a circle surrounded by an arc and two radii.

Analysis:

Area of a sector = ∅/360 x πr^{2}

∅ = 75°

r = 24 units

Area of sector = 75/360 x π(24)^{2} = 120\pi square units

In conclusion, the area of the associated sector is 120π square units

Learn more about sector : brainly.com/question/22972014

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2 years ago
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