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Eva8 [605]
3 years ago
7

Breakfast eaten and the slim camp-outfit lashed to the sled, the men turned their backs on the cheery fire and launched out into

the darkness. At once began to rise the cries that were fiercely sad—cries that called through the darkness and cold to one another and answered back. Conversation ceased. Daylight came at nine o'clock. At midday the sky to the south warmed to rose-colour, and marked where the bulge of the earth intervened between the meridian sun and the northern world. But the rose-colour swiftly faded. The grey light of day that remained lasted until three o'clock, when it, too, faded, and the pall of the Arctic night descended upon the lone and silent land.
As darkness came on, the hunting-cries to right and left and rear drew closer—so close that more than once they sent surges of fear through the toiling dogs, throwing them into short-lived panics.

At the conclusion of one such panic, when he and Henry had got the dogs back in the traces, Bill said:

"I wisht they'd strike game somewheres, an' go away an' leave us alone."

"They do get on the nerves horrible," Henry sympathized.

They spoke no more until camp was made.

Read this line from the story:
As darkness came on, the hunting-cries to right and left and rear drew closer, ...

What is the purpose of this sentence in the story? (5 points)

It implies a mood of utter despair.
It implies a near tragic event.
It creates a feeling of being trapped.
It creates a sense of action. I AM GIVING 50 POINTS!!!!!!!!!!!!!!!!!
Mathematics
1 answer:
Olenka [21]3 years ago
8 0

Answer:

A

Step-by-step explanation:

The problem with this kind of question is that the author tells you what you should see in that sentence. The dogs experienced fear. Any other answer you suggest is not what the author means. So you are guessing. It is adding to the notion that the arctic is not a friendly place and you cannot go sunbathing in and be comfortable in the middle of winter.

A is as good an answer as you are likely to get, but I don't think it's right.

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Please help me with this please and thank you
Alina [70]

Step-by-step explanation:

y = ax^n + bx^(n-1) ... + z

(0, 1) tells us that the constant term z = 1.

because x = 0 eliminates all other terms. and as the sum is 1, that means z = 1.

for the other pairs I strongly suspect

(-1, 3) : 2×(-1)² + 1 = 2×1 + 1 = 3

(-2, 9) : 2×(-2)² + 1 = 2×4 + 1 = 9

so, the fitting equation is

y = 2x² + 1

3 0
2 years ago
What is the length of side a? Round to the nearest tenth of an inch. <br><br> Please and thank youuu
lord [1]

Answer:

using Pythagoras rule, 16^2 -7^2 =a^2

so 256-49 = 297.

√207 =14.38 to the nearest tenth of an inch is 14inch.which is your answer

6 0
2 years ago
Why is 560-500 over 500 multiplied by 100?
Lady_Fox [76]

Answer:

12

Step-by-step explanation:

560-500=60

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5 0
3 years ago
Read 2 more answers
Devan spent 14 of her paycheck at the mall. She spent 12 of that money on shoes. What fraction of her total paycheck did she spe
Alla [95]
She spent 12 of her paycheck and had 2 more
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3 years ago
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Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
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