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vazorg [7]
3 years ago
10

Help me please !! give me right answer .

Mathematics
1 answer:
harina [27]3 years ago
4 0

Answer:

2.04

Step-by-step explanation:

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What value of x will make the equation true
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Answer:

5 is the value of x

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Find an equation for the perpendicular bisector of the line segment whose endpoints are ( − 1 , − 1 ) (−1,−1) and ( 9 , 7 ) (9,7
Hunter-Best [27]

Answer:

Place the compass at one end of line segment.

Adjust the compass to slightly longer than half the line segment length.

Draw arcs above and below the line.

Keeping the same compass width, draw arcs from other end of line.

Place ruler where the arcs cross, and draw the line segment.

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On a recent homework assignment, Eli needed to solve the equation
tamaranim1 [39]

Answer:

A - the real answer is 7

Step-by-step explanation:

g²=49 (square root 49 to get 7)

B) not sure - possibly wrote the negative sign as a mistake

7 0
3 years ago
Given: △ABC, AB=5sqrt2 <br> m∠A=45°, m∠C=30°<br> Find: BC and AC
Marysya12 [62]

BC is 10 units and AC is 5+5\sqrt{3} units

Step-by-step explanation:

Let us revise the sine rule

In ΔABC:

  • \frac{AB}{sin(C)}=\frac{BC}{sin(A)}=\frac{AC}{sin(B)}
  • AB is opposite to ∠C
  • BC is opposite to ∠A
  • AC is opposite to ∠B

Let us use this rule to solve the problem

In ΔABC:

∵ m∠A = 45°

∵ m∠C = 30°

- The sum of measures of the interior angles of a triangle is 180°

∵ m∠A + m∠B + m∠C = 180

∴ 45 + m∠B + 30 = 180

- Add the like terms

∴ m∠B + 75 = 180

- Subtract 75 from both sides

∴ m∠B = 105°

∵ \frac{AB}{sin(C)}=\frac{BC}{sin(A)}

∵ AB = 5\sqrt{2}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{BC}{sin(45)}

- By using cross multiplication

∴ (BC) × sin(30) = 5\sqrt{2} × sin(45)

∵ sin(30) = 0.5 and sin(45) = \frac{1}{\sqrt{2}}

∴ 0.5 (BC) = 5

- Divide both sides by 0.5

∴ BC = 10 units

∵ \frac{AB}{sin(C)}=\frac{AC}{sin(B)}

- Substitute AB and the 3 angles in the rule above

∴ \frac{5\sqrt{2}}{sin(30)}=\frac{AC}{sin(105)}

- By using cross multiplication

∴ (AC) × sin(30) = 5\sqrt{2} × sin(105)

∵ sin(105) = \frac{\sqrt{6}+\sqrt{2}}{4}

∴ 0.5 (AC) = \frac{5+5\sqrt{3}}{2}

- Divide both sides by 0.5

∴ AC = 5+5\sqrt{3} units

BC is 10 units and AC is 5+5\sqrt{3} units

Learn more:

You can learn more about the sine rule in brainly.com/question/12985572

#LearnwithBrainly

6 0
3 years ago
Identify an equation in point slope form for the line parallel to y=1/2x-7 that passes through (-3,-2)
ANTONII [103]

Answer:

Step-by-step explanation:

The point slope form of a straight line is expressed as

y - y1 = m(x - x1)

Where

m represents slope of the line

y1 represents the initial value of y

x1 represents the initial value of x

If two lines are parallel, it means that they have the same slope. From the equation of the given line, slope = 1/2

Therefore,

m = 1/2

x1 = - 3

y1 = - 2

Substituting into the point slope equation, it becomes

y - - 2 = 1/2(x - - 3)

y + 2 = 1/2(x + 3)

The equation is

y + 2 = 1/2(x + 3)

4 0
3 years ago
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