Help me please !! give me right answer .

Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu

Luda [366]

Answer:

11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

P(z ≤ -6) ≈ 9.86588×10^-10

and

P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

0.50^t = 0.000290372

t·log(0.50) = log(0.00290372) . . . . take logarithms

t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0

3 years ago

15. ¿Cuál es ol rosultado de 2x(x - 1)?

professor190 [17]

<h2>Explicación paso a paso Espero que te ayude</h2>

$2x(x - 1) \\ \\ {2x}^{2} - 2x$

<h2>Espero que te ayude </h2>

5 0

2 years ago

Read 2 more answers

A = 6 and b = 24 work out the values a) a+b b) ab c) b/a d) d) (a+b)^2

Oksanka [162]

Answer:

a) 30

b) 144

c) 4

d) 900

Step-by-step explanation:

a) 6 + 24 = 30

b) 6 * 24 = 144

c) 24 ÷ 6 = 4

d) $30^2=900$

5 0

2 years ago

Read 2 more answers

If two events a and b are independent and you know that p(a) = 0.65, what is the value of p(a | b)?

Ksivusya [100]

Let's think of an example which would better help visualize this situation.

1) Someone exercises a lot so they can concentrate more on their homework (here running and concentration on homework are dependent events)

2) Someone exercises a lot because they wear a blue t-shirt (here, you can clearly see that wearing a blue shirt and exercising are not related. These events are independent).

Now concentrating on P(a | b) = Probability a occurred if b occurred.

It does not matter if b occurred (just like it didn't matter that the person wore a blue shirt which meant that they exercised) for the outcome a to occur.

Therefore, probability of P(a | b) = P(a)

P(a | b) = 0.65

Hope I helped :)

5 0

3 years ago

An urn contains three red balls and four blue balls. Draw two balls at random from the urn, without replacement. Compute the exp

mezya [45]

Step-by-step explanation:

in total we have 3+4 = 7 balls.

when we draw the first ball, the probability to draw a red ball is 3/7, and a blue ball 4/7.

when we draw the second ball, we have now only 6 balls in total.

the probabilty to draw a red back now depends also on the result of the first draw.

if the first ball was already red, then we have only a chance now of 2 out of 6.

if the first ball was blue, then we have now a chance of 3 out of 6.

so, the probably to draw at least 1 red ball in 2 draws is the probability of drawing one on the first draw plus the probability of drawing one on the second :

1 - probability to see 2 blue balls

1 - 4/7 × 3/6 = 1 - 12/42 = 30/42 = 0.714285714...

the expected number of red balls in 2 draws is

1 red in first red in first red in second

but not second and second but not first

1×(3/7 × 4/6) + 2×(3/7 × 2/6) + 1×(4/7 × 3/6) = 12/42 + 12/42 + 12/42 = 36/42 = 6/7 = 0.857142857 ≈ 0.8571

7 0

2 years ago