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Fiesta28 [93]
3 years ago
5

Given: △ABC, E∈ AB m∠ABC=m∠ACE AB=34, AC=20 Find: AE

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:

AE = 11.76 units

Step-by-step explanation:

For better understanding of the solution, see the attached figure :

Given : E ∈ AB, m∠ABC = m∠ACE, AB = 34 and AC = 20

To find AE :

In ΔABC and ΔACE,

m∠ABC = m∠ACE ( Given )

∠A = ∠A    ( Common angle for both the triangles )

By AA postulate of similarity of triangles, ΔABC ~ ΔACE

So, proportion of the corresponding will be equal.

\implies \frac{AC}{AB}=\frac{CE}{BC}=\frac{AE}{AC}\\\\\implies\frac{AC}{AB}=\frac{AE}{AC}\\\\\implies\frac{20}{34}=\frac{AE}{20}\\\\\implies AE=\frac{20\times 20}{34}\approx 11.76

Hence, AE = 11.76 units

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Step-by-step explanation

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To get <F, we will use the expression

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The product of two numbers is 41. One of the numbers
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<h3>Answer:   5 - 4i     (choice A)</h3>

===================================================

Work Shown:

x = the other number

(5+4i)*x = 41

x = 41/(5+4i)

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x = 41*(5-4i)/( 41 )

x = (41/41)*(5-4i)

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As a way to check, (5+4i)*(5-4i) = 5^2+4^2 = 25+16 = 41

The rule used is (a-bi)(a+bi) = a^2 + b^2

-----------

Note:  I multiplied top and bottom by (5-4i) to get rid of the imaginary term in the denominator.

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Step-by-step explanation:

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Read 2 more answers
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