Question

Four times a number plus three times a second number is -9. Twice the first number plus the second number is three. Find the numbers.

Answer 1

Answer:

The first number is: 9

and the second number is: -15

Step-by-step explanation:

Let the first number be : a

and the second number be: b

Now, we have:

Four times a number plus three times a second number is -9.

i.e. we have : 4a+3b= -9--------(1)

Also,

Twice the first number plus the second number is three.

i.e. 2a+b=3

i.e. we have: b=3-2a------(2)

Now, putting the value of b in equation (1) we have:

$4a+3(3-2a)=-9\\\\4a+3\times 3-3\times 2a=-9\\\\4a+9-6a=-9\\\\4a-6a=-9-9\\\\-2a=-18\\\\2a=18\\\\a=\dfrac{18}{2}\\\\a=9$

and on putting the value of a in equation (2) we have:

$b=3-2\times 9\\\\b=3-18\\\\b=-15$

Answer 2

Answer:

Step-by-step explanation:

3