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3 years ago

Find the slope of the line that is parallel and perpendicular -7x-2y=4

1 answer:

5 0

$\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{7}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{7}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{7}}}$

now, what's the slope of a line parallel to that one above? well, parallel lines have exactly the same slope.

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Find the area. A. 19 ft² B. 30 ft² C. 31 ft² D. 84 ft²

JulijaS [17]

Answer: D. 84 ft^2

Step-by-step explanation: The area of a trapezoid is (a+b)/2 x h. A and B are the bases, and h is the height. Plug in the numbers.

(8+16)/2 x 7 = 84

Your answer would be 84 ft^2. D.

8 0

3 years ago

Determine an equation in simplified form for the family of quartic functions with zeros at 1, -4, (-2+i) and (-2-i). Give your a

k0ka [10]

Hello :
an equation :
(x-1)(x+4)(x+2-i)(x+2+i)

7 0

3 years ago

Given the regular octagon shown below, what is the measure of angle x?

vladimir1956 [14]

Answer:

$x=45$ °

Step-by-step explanation:

The angle shown in the figure is known as an external angle.

Also, in a regular polygon (like the regular octagon) the sum of all the exterior angles is the same regardless of the number of sides of the figure:

$360$ °

And to find the measure of a single external angle (such as the angle $x$ shown in the figure) we must divide 360 ° by the number of sides n:

$\frac{360}{n}$

and for the regular octagon, since it has 8 sides:

$n=8$

so the value of x is:

$x=\frac{360}{n}\\ \\x=\frac{360}{8}\\ \\x=45$ °

the measure of angle x is 45° which is the second option

3 0

3 years ago

Let (-7, 2) be a point on the terminal side of 0.

nekit [7.7K]

By applying the definitions of trigonometric functions, the exact values of the sine, secant and tangent of the point on the terminal side are $\sin \theta = \frac{2}{\sqrt{53}}$ , $\sec \theta = -\frac{\sqrt{53}}{7}$ and $\tan \theta = -\frac{2}{7}$ .

<h3>How to determine the exact values</h3>

In this question we need to find the exact values of three trigonometric functions associated with the terminal side of an angle. The following definitions are used:

Sine

$\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}$ (1)

Secant

$\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}$ (2)

Tangent

$\tan \theta = \frac{y}{x}$ (3)

If we know that x = - 7 and y = 2, then the exact values of the three trigonometric functions:

Sine

$\sin \theta = \frac{2}{\sqrt{53}}$

Secant

$\sec \theta = -\frac{\sqrt{53}}{7}$

Tangent

$\tan \theta = -\frac{2}{7}$

<h3>Remark</h3>

The statement reports typing errors, correct form is shown below:

Let (x, y) = (- 7, 2) be a point on the terminal side of θ. Find the exact value of sin θ, sec θ and tan θ.

To learn more on trigonometric functions: brainly.com/question/6904750

#SPJ1

5 0

1 year ago

Does anyone know if 4 can go into 72

Nuetrik [128]

4 can go into 72 18 times

8 0

3 years ago

Read 2 more answers