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3 years ago

Can someone plz help me with this math problem.

Mathematics

2 answers:

Anettt [7]3 years ago

3 0

I dont know if this is what your looking for but i think it is

Kitty [74]3 years ago

3 0

Surface area is much easier then area in this case.

You would just find the area of each side, and since you know the slant height, if you were to take each side of the pyramid as a 2D figure, the base would be 6.4 inches as stated and the height 6.1, because if you look at where the slant height is and basically took a side as a 2D figure, it would be the same as the height.

Pretty sure most people know how to find the area of a triangle, but it's base * height / 2, or 6.4 * 6.1 / 2, or 19.52. Since there are four of these triangle side things, just multiply 19.52 by 4, to get 78.08.

There's still a square base, so just multiply 6.4 by itself to get 40.96.

Now just add the two together to get 119.04.

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fgiga [73]

A rational number .... where q is not zero.

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3 years ago

If B is the midpoint of AC, and AC=8x-20, find BC.

Natali5045456 [20]

2(3x-1)=8x-20
SIMPLY

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3 0

3 years ago

Read 2 more answers

Solve for x. x2 = 64

Fed [463]

Answer:

32 × 2 = 64

Step-by-step explanation:

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3 years ago

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Help(T_T) "Give 7.897 correct to 2 decimal places"

Lynna [10]

Answer:

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7 0

2 years ago

Suppose you were considering going bungee jumping, but would only go if the mean breaking strength of the cord was greater than

serg [7]

Answer:

Type II error will occur when we conclude that the mean breaking strength of the cord is smaller than or equal to 250 pounds but in actual it was not true.

Step-by-step explanation:

We are given that you are considering going bungee jumping, but would only go if the mean breaking strength of the cord was greater than 250 pounds.

If the mean breaking strength of the cord is greater than 250 pounds, the bungee cord will not break.

Let $\mu$ = mean breaking strength of the cord

So, Null Hypothesis, $H_0$ : $\mu \leq$ 250 pounds

Alternate Hypothesis, $H_A$ : $\mu$ > 250 pounds

Here, null hypothesis states that the mean breaking strength of the cord was smaller than or equal to 250 pounds.

On the other hand, alternate hypothesis states that the mean breaking strength of the cord was greater than 250 pounds.

Now, Type II error states the Probability of accepting null hypothesis given the fact that it was false or Probability of accepting the false hypothesis.

SO, according to our question, Type II error will occur when we conclude that the mean breaking strength of the cord is smaller than or equal to 250 pounds but in actual it was not true and he mean breaking strength of the cord was greater than 250 pounds.

8 0

3 years ago