Option C is correct
The value of h(f(x)) is, x
Inverse function:
An inverse function that undergoes the other function.
For example: if f(x) is the inverse of g(x) then;
for every x.
As per the statement:
If h(x) is the inverse of f(x).
by definition of inverse:
Therefore, the value of h(f(x)) is, x
Answer:
![-\frac{6}{4}](https://tex.z-dn.net/?f=-%5Cfrac%7B6%7D%7B4%7D)
Step-by-step explanation:
The first 2 numbers cancel, and -15/4+9/4 is the same as 9/4 - 15/4
Please mark me as brainliest if I am correct
Answer: 793 mi/h
Step-by-step explanation:
We have the following data:
is Earth radius at the 40th parallel of north latitude
is the Earth's angular velocity (toward the east)
is the Jet's angular velocity (toward due west)
And we need to find the Jet's speed
, which is calculated by:
![V_{J}=\omega_{J}R_{E}](https://tex.z-dn.net/?f=V_%7BJ%7D%3D%5Comega_%7BJ%7DR_%7BE%7D)
![V_{J}=(\frac{\pi}{12} rad/h)(3030 mi)](https://tex.z-dn.net/?f=V_%7BJ%7D%3D%28%5Cfrac%7B%5Cpi%7D%7B12%7D%20rad%2Fh%29%283030%20mi%29)
![V_{J}=793.25 mi/h](https://tex.z-dn.net/?f=V_%7BJ%7D%3D793.25%20mi%2Fh)
Answer: 37 units
Step-by-step explanation:
This also works as the height of the triangle.
This also works as the base of the triangle.
Let's call pink ''a'', and blue ''b''. The side we're looking for ''c'' is the hypothenuse.
To find the values of a and b, use the area formula of a square and solve for a side. In this case, since we're going to need the squared values, this step can be omitted.
![Formula: A=s^2](https://tex.z-dn.net/?f=Formula%3A%20A%3Ds%5E2)
![s=\sqrt[]{A}](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7BA%7D)
Let's work with Blue.
![s=\sqrt[]{144units^2} \\s=12units](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7B144units%5E2%7D%20%5C%5Cs%3D12units)
Now Pink.
![s=\sqrt[]{1225units^2}\\s=35units](https://tex.z-dn.net/?f=s%3D%5Csqrt%5B%5D%7B1225units%5E2%7D%5C%5Cs%3D35units)
So we have a triangle with a base of 35 units and a height of 12 units.
Now let's use the pythagoream's theorem to solve.
![c^2=a^2+b^2\\c=\sqrt[]{a^2+b^2} \\c=\sqrt[]{(12units)^2+(35units)^2}\\c=\sqrt[]{144units^2+1225units^2}\\ c=\sqrt[]{1369units^2}\\ c=37units](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2%5C%5Cc%3D%5Csqrt%5B%5D%7Ba%5E2%2Bb%5E2%7D%20%5C%5Cc%3D%5Csqrt%5B%5D%7B%2812units%29%5E2%2B%2835units%29%5E2%7D%5C%5Cc%3D%5Csqrt%5B%5D%7B144units%5E2%2B1225units%5E2%7D%5C%5C%20c%3D%5Csqrt%5B%5D%7B1369units%5E2%7D%5C%5C%20c%3D37units)
Answer:
at time in 7:30 am - 5:00 pm on Sunday to Tuesday
Step-by-step explanation:
the reason i choose that because of rush hour happens during schools drop/release times.
that's the best that i can think of.
; )