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3 years ago

100 x 54 + 77 ÷ 2 = ? (RIGHT ANSWER GETS BRAINLIEST)

Mathematics

2 answers:

stealth61 [152]3 years ago

7 0

Answer:

So 2,738.5

Step-by-step explanation:

100×54 equals

— 5,400

5,400+77 equals

—5,477

5,477÷2 equals

—2,738.5

The answer is 2,738,5

Nadusha1986 [10]3 years ago

6 0

Answer:

5438.5

Step-by-step explanation:

To complete this equation, we must use the order of operations also known as PEMDAS.

For the case of this problem, we start by multiplying or dividing numbers before adding or subtracting numbers.

First let's start on the left:

100 x 54 + 77 ÷ 2

5,400 + 77 ÷ 2

5,400 + 38.5

5438.5

I hope this helps! Just remember to always add or subtract number last and start on the left, so that you don't get confused.

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Determine which ratio forms a proportion with 6/9

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Idk for sure but im thinking 8/12? idk sorry

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3 years ago

8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.

According to that, if $a + b = 0$ , then $a = 0$ and $b = 0$ .

7 0

3 years ago

A local print shop has a big order of pamphlets to print, so they decide to use two of their printers for the one job. The newes

nlexa [21]

If both printers work together. Then the number of the pamphlets will be 20x in four hours.

<h3>What is Algebra?</h3>

Algebra is the study of mathematical symbols, and the rule is the manipulation of those symbols.

A local print shop has a big order of pamphlets to print, so they decide to use two of their printers for the one job.

The newest printer can print the pamphlets four times as fast as the old printer Working together the printers can complete the job in 4 hours.

Let x be the number of the pamphlets are printed by the old printer in one hour.

Then the number of the pamphlets are printed by the new printer in one hour will be 4x.

Then if they work together, then the number of the pamphlets in one hour will be 5x.

Then the number of the pamphlets in 4 hour will be

→ 5x × 4

→ 20x

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ1

6 0

1 year ago

Answer? .............................

kumpel [21]

ANSWER TO QUESTION ONE IS 5

5x2+5=15

5-4=1

15x1=15

QUESTION 2

X = 20

IDK 3 :(

7 0

3 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago