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3 years ago

100 x 54 + 77 ÷ 2 = ? (RIGHT ANSWER GETS BRAINLIEST)

Mathematics

2 answers:

stealth61 [152]3 years ago

7 0

Answer:

So 2,738.5

Step-by-step explanation:

100×54 equals

— 5,400

5,400+77 equals

—5,477

5,477÷2 equals

—2,738.5

The answer is 2,738,5

Nadusha1986 [10]3 years ago

6 0

Answer:

5438.5

Step-by-step explanation:

To complete this equation, we must use the order of operations also known as PEMDAS.

For the case of this problem, we start by multiplying or dividing numbers before adding or subtracting numbers.

First let's start on the left:

100 x 54 + 77 ÷ 2

5,400 + 77 ÷ 2

5,400 + 38.5

5438.5

I hope this helps! Just remember to always add or subtract number last and start on the left, so that you don't get confused.

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In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

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3 years ago

Josephine noticed that out of 10 e-mails she received, 7 were advertisements. What can she predict about the number of advertise

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3 years ago

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Find the least common denominator of 7 and X+4 x-4

Effectus [21]

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2 years ago

Which values are solutions to the inequality below? Check all that apply. Sqrt x > 8

Sophie [7]

Answer:

64 is the right answer of your question

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2 years ago

Christine is putting money into a savings account. She starts with $650 in the savings account, and each week she adds $60. Let

TEA [102]

Total amount of money in the savings account after 11 weeks is $1310.

Total money in the account =

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Thus total amount of money in the savings account after 11 weeks is $1310.

Learn more about Linear Equations here :

brainly.com/question/2263981

#SPJ1

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1 year ago