We know that
sin²x+cos²x=1
so
clear cos x
cos x=(+/-)√[1-sin²x]
in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5
the answer is
cos o=√21/5
Subtract them left to right
The answer is 0, anything divided by 0 automatically cancels out.
(-19,7) (4, 15) hshw wjwhw
Answer:
C. 7/9 and 0.7 (with bar notation)
Step-by-step explanation:
The division keeps going with the remainder as 7 and 9 can only go into 70 with a 63 so to show the 7 keeps going you would have to use bar notation above 7.
