The statistical method would be the least squares regression. (: I hope all is well and you end up passing. Good luck, rockstar!
Answer:
Explanation:
Kaleb Konstruction, Inc., has the following mutually exclusive projects available. The company has historically used a three-year cutoff for projects. The required return is 12 percent.Year Project F Project G0 –$ 126,000 –$ 196,000 1 64,500 44,500 2 45,500 59,500 3 55,500 85,500 4 50,500 115,500 5 45,500 130,500 Required:(a) Calculate the payback period for both projects. (Do not round intermediate calculations. Round your answers to 2 decimal places (e.g., 32.16).)Payback period Project F years Project G years(b) Calculate the NPV for both projects. (Do not round intermediate calculations. Round your answers to 2 decimal places (e.g., 32.16).)Net present value Project F $ Project G $ (c) Which project should the company accept?
Answer:
C. Accrued expense
Explanation:
Because the expense has already been incurred, but not yet paid, it is an accrued expense.
Answer:
A. Debit: Bad Debt Expense 2,500
Credit: Allowance for Doubtful Accounts 2,500
250,000 x .01 = 2,500
B. Debit: Bad Debt Expense 2,750
Credit: Allowance for Doubtful Accounts 2,750
3,000 - 250 = 2,750
Answer:
A. D1 = 1.50*1.06 = 1.59
D2 = 1.59*1.06 = 1.69
D3 = 1.69*1.06 = 1.79
B. PV of D1=(1.50*1.06)/1.13^1=1.41
PV of D2=(1.50*1.06^2)/1.13^2=1.32
PV of D3=(1.50*1.06^3)/1.13^3=1.24
PV of all dividend = (1.50*1.06)/1.13^1 + (1.5*1.06^2)/1.13^2 + (1.5*1.06^3)/1.13^3
PV of all dividend = 1.59/1.13 + 1.6854/1.2769 + 1.786524/1.442897
PV of all dividend = 1.407079646 + 1.319915 + 1.238150748
PV of all dividend = 3.965145814288893
PV of all dividend = 3.97
C. PV = 27.05/(1+13%)^3
PV = 27.05/(1.13)^3
PV = 27.05/1.442897
PV = 18.74701
PV = 18.75
D. The most you should pay for it
:
= (1.50*1.06)/1.13^1+(1.5*1.06^2)/1.13^2+(1.5*1.06^3)/1.13^3+27.05/1.13^3
=22.71
E. Value = (1.50*1.06)/(13%-6%)
Value = 1.59 / 7%
Value = 1.59 / 0.07
Value = 22.714286
Value =22.71
F. No, the value is not dependent on the holding period, you can see from above that the value of infinite time period estimated in E equals to the value calculated when there was 3 years holding period.