Answer:
Step-by-step explanation:
Equations are commonly used in scienctific discoveries to calculate power, work, distance, and time. It is also common to use the circumference and area equations to help with construction and design. Overall, math is a very important part of our lives, and it is also important to learn about it.
Megan:
x to the one third power =

<span>x to the one twelfth power = </span>

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>

<span>
Since </span>

then

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

Julie:
x times x to the second times x to the fifth = x * x² * x⁵
<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>
![\sqrt[32]{x* x^{2} * x^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B32%5D%7Bx%2A%20x%5E%7B2%7D%20%2A%20x%5E%7B5%7D%20%7D%20)
<span>
Since </span>

Then
![\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B32%5D%7Bx%2A%20x%5E%7B2%7D%20%2A%20x%5E%7B5%7D%20%7D%3D%20%5Csqrt%5B32%5D%7B%20x%5E%7B1%2B2%2B5%7D%20%7D%20%3D%5Csqrt%5B32%5D%7B%20x%5E%7B8%7D%20%7D)
Since
![\sqrt[n]{x^{m}} = x^{m/n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%20%3D%20x%5E%7Bm%2Fn%7D%20%7D%20)
Then
![\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}](https://tex.z-dn.net/?f=%5Csqrt%5B32%5D%7B%20x%5E%7B8%7D%20%7D%3D%20x%5E%7B8%2F32%7D%20%3D%20x%5E%7B1%2F4%7D%20)
Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
Answer:
B) 10
Step-by-step explanation:
6 + 4 = 10
<span>Justification
Step 1: Let a = b.
Step 2: Then a^2 = ab ,
Step 3: a^2 + a^2 = a^2 + ab ,
Step 4: 2a^2=a^2 + ab,
Step 5: 2a^2 - 2ab = a^2 + ab - 2ab,
Step 6: and 2a^2 - 2a^b = a^2 + ab - 2ab .
Step 7: This can be written as 2(a^2 - ab) = 1(a^2 - ab) ,
Step 8: and cancelling the (a^2 - ab) from both sides gives 1 = 2.</span>
Answer:
0.35
Step-by-step explanation:
this is the answer.........