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2 years ago

What is the slope of the line that passes through the point (9,4) and (3,9)?

Mathematics

1 answer:

Fantom [35]2 years ago

8 0

Step-by-step explanation:

m is for slope of the line that passes through

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{9 - 4}{3 - 9}$

$m = \frac{5}{ - 6} = - \frac{5}{6}$

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A rectangle has a length of (x+10) centimeters and a width of x centimeters. If the perimeter is 32 centimeters, what is the len

I am Lyosha [343]

Given:

Length of rectangle = (x+10) cm

Width of the rectangle = x cm

Perimeter = 32 cm

To find:

The length of the rectangle.

Solution:

We know that,

$Perimeter=2(l+w)$

Where, l is length and w is width.

Substituting the values, we get

$32=2((x+10)+x)$

$32=2(2x+10)$

$32=4x+20$

Subtract 20 from both sides.

$32-20=4x$

$12=4x$

Divide both sides by

$3=x$

So, the length is

$3+10=13$

Therefore, the length of the rectangle is 13 cm.

7 0

3 years ago

A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In

lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of males having blood disorder= $\frac{250}{1000}$ = 0.25

$\hat p_2$ = sample proportion of females having blood disorder = $\frac{275}{1000}$ = 0.275

$n_1$ = sample of males = 1000

$n_2$ = sample of females = 1000

$p_1$ = population proportion of males having blood disorder

$p_2$ = population proportion of females having blood disorder

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between the population proportions, ( $p_1-p_2$ ) is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

P( $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ( $p_1-p_2$ ) < $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

95% confidence interval for ( $p_1-p_2$ ) =

[ $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ , $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ]

= [ $(0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ , $(0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ ]

= [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0

3 years ago

the coordinates of points a and b are (2,4) and (-2,-4) respectively. what is the slope of the line that connects the two points

solmaris [256]

we are given two points as

(2,4) and (-2,-4)

Let's assume

first point as (x1,y1)=(2,4)

so, x1=2 and y1=4

Second point as (x2,y2)=(-2,-4)

so, x2=-2 and y2=-4

now, we can use slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{-4-4}{-2-2}$

now, we can simplify it

$m=2$

so, slope is 2 ..................Answer

4 0

3 years ago

The diameter of a ball is 8 in.

Cerrena [4.2K]

267. 95cm^3

hope this helped

5 0

3 years ago

A=2/3b,b=15,c=? please help dear lord

SVETLANKA909090 [29]

Answer:

10.

Divide b into thirds, and then add together 2 of those thirds.

15/3 = 5

5x2 is 10.

Sorry if that doesn't make sense but it's how I do it in my head lol.

5 0

3 years ago

What is the slope of the line that passes through the point (9,4) and (3,9)?​

What is the slope of the line that passes through the point (9,4) and (3,9)?