1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bazaltina [42]
2 years ago
14

What is the slope of the line that passes through the point (9,4) and (3,9)?​

Mathematics
1 answer:
Fantom [35]2 years ago
8 0

Step-by-step explanation:

m is for slope of the line that passes through

m =  \frac{y_2 - y_1}{x_2 - x_1}

m =  \frac{9 - 4}{3 - 9}

m =  \frac{5}{ - 6}  =  -  \frac{5}{6}

You might be interested in
5=1/2x - 3 please help me out
liq [111]

Answer:

x = 16

Step-by-step explanation:

5 = 1/2(x) - 3

Add 3 to both sides.

8 = 1/2(x)

Rewrite for clarity.

1/2(x) = 8

x/2 = 8

Multiply both sides by 2.

x = 16.

Proof:

5 = 1/2(x) - 3

Substitute variable.

5 = 1/2(16) - 3

Multiply 1/2 and 16.

5 = 8 - 3

Subtract 3 from 8.

5 = 5

3 0
3 years ago
can someone please help me find the surface area of the pyramid with an equilateral triangle for a base
ioda

To obtain the total surface we have to calculate the surface of the 4 triangles and add up the areas (remember that the area of a triangle is (b*h)/2 , b is the base, h is the height ).

We will caculate first the area of the base triangle for that we considerer the fact that it is an equilateral triangle with sides of lenght 6 cm, now we calculate the height, I am going to draw please wait a moment

using the pythagorean theorem we have that

\begin{gathered} h^2=6^2cm^2-3^2\operatorname{cm}=27cm^2 \\ h=\text{ }\sqrt[]{27\text{ }}cm \end{gathered}

Then, the area of the triangle is 6*h/2 = 3h = 15.59 cm^2.

Now we calculate the area of the other 3 triangles, notice that those triangles have the same base and height so we will calculate for one of them and multiply by 3. From the image we know that the height is 15cm and the base is 6 cm so the area is 45cm^2, and 45*3 cm^2 = 135cm^2.

Finally we add up all the areas:

135cm^2+15.59cm^2=150.59cm^2

6 0
9 months ago
In August 200920092009, Usain Bolt ran 100100100 meters in 9.589.589, point, 58 seconds (\text{sec})(sec)left parenthesis, start
Sveta_85 [38]

Answer:

<u>Usain Bolt's average speed in yards per second was 11.4</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

World record of Usain Bolt = 9.589 seconds

Distance of the world record = 100 meters

1 yard = 0.9144 meters ⇒ 100 meters = 109.36 yards

2. What was Usain Bolt's average speed in yards per second?

Let's recall that the formula of speed is:

Speed = Distance/Time

Replacing with the values we know:

Usain Bolt's Speed = 109.36/9.589

<u>Usain Bolt's Speed = 11.4 yards per second (Rounding to one decimal place)</u>

6 0
3 years ago
What is 2+2 <br> I'm really am wondering
Delvig [45]
4 is the answer to 4+4
8 0
2 years ago
Read 2 more answers
The values of didgets in 58
daser333 [38]
One and tens ar the didgets
4 0
3 years ago
Other questions:
  • I don't know why its correct. Help explain to me pls.
    10·1 answer
  • Apply the distributive property to create an equivalent expression. 2(3-8y)
    14·2 answers
  • PLEASE HELPPPP ! 16^x=64^x+4
    7·1 answer
  • Question 6<br> 6. Find the length of line segment AB.
    5·1 answer
  • How do you graph x = 40?
    7·2 answers
  • How much would you pay for a boat that costs $35,000 if you buy it on
    5·1 answer
  • Can someone please help me with geometry. Honestly I need help. Let me know please! :)
    13·1 answer
  • Graph the image of this figure after a dilation with a scale factor of 12centered at the origin.
    5·1 answer
  • Pls show working 3 friends shared the driving on a long trip. Marla drove 7 miles more than Guido. Guido drove five times as far
    11·2 answers
  • Simplify the expression:<br> (6x² − x + 5)<br> minus<br> (8x² + 8x-7)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!