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Ilia_Sergeevich [38]
3 years ago
5

Whereas < is called a relational operator, x < y is called a(n) ________. A) Arithmetic operator B) Relative operator C) R

elational expression D) Largeness test E) None of these
Computers and Technology
1 answer:
Westkost [7]3 years ago
3 0

Answer:

The answer is "Option C".

Explanation:

Relational expression are one or more variable and maybe even values, which operators have linked together. It is also known as the process, which is used to calculate the outcome, that is generated by the relational expression. These words are typically designed to answer the questions in boolean values, and other options were not correct, that can be described as follows:

  • In option A, This process is used to perform the mathematical operation, that's why it is not correct.
  • Option B and Option D both is used to compare values, that's why it is not correct.
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Write a Java program to encrypt and decrypt a phrase using two similar approaches, each insecure by modern standards. The first
xeze [42]

Answer:

See explaination

Explanation:

//CryptoManager.java

public class CryptoManager {

static int LOWER_BOUND=32;

static int UPPER_BOUND=95;

/*This method determines if a string is within the allowable bounds of ASCII

codes according to the LOWER_BOUND and UPPER_BOUND characters. The parameter

plainText is the string to be encrypted. The method returns true if all

characters are within the allowable bounds, false if any character is outside.*/

public static boolean stringInBounds (String plainText)

{

boolean flag=true;

//determines if a string is within the allowable bounds of ASCII

//codes according to the LOWER_BOUND and UPPER_BOUND characters.

for(int i=0;i<plainText.length();i++)

{

if(!((int)plainText.charAt(i)>=LOWER_BOUND && (int)plainText.charAt(i)<=UPPER_BOUND))

{ //false if any character is outside the bounds

flag=false;

break;

}

}

//returns true if all characters are within the allowable bounds

return flag;

}

/*This method encrypts a string according to the Caesar Cipher. The integer key

specifies an offset and each character in plainText is replaced by the character

the specified distance away from it. The parameter plainText is an uppercase

string to be encrypted. The parameter key is an integer that specifies the

offset of each character. The method returns the encrypted string.*/

public static String encryptCaesar(String plainText, int key)

{

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//encrypted text

String res="";

//encryption

for(int i=0;i<plainText.length();i++)

{

res+=Character.toString((char) ((int)plainText.charAt(i)+key));

}

//return result

return res;

}

/* This method decrypts a string according to the Caesar Cipher. The integer

key specifies an offset and each character in encryptedText is replaced by

the character "offset" characters before it. This is the inverse of the

encryptCaesar method. The parameter encryptedText is the encrypted string

to be decrypted, and key is the integer used to encrypt the original text.

The method returns the original plain text string.*/

public static String decryptCaesar(String encryptedText, int key){

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//decrypted text

String org="";

//encryption

for(int i=0;i<encryptedText.length();i++)

{

org+=Character.toString((char) ((int)encryptedText.charAt(i)-key));

}

//return result

return org;

}

public static int Wrap_around(int key)

{

while(key>UPPER_BOUND)

{

key-=(UPPER_BOUND-LOWER_BOUND);

}

return key;

}

/* This method encrypts a string according to the Bellaso Cipher. Each character

in plainText is offset according to the ASCII value of the corresponding

character in bellasoStr, which is repeated to correspond to the length of

plaintext. The method returns the encrypted string.*/

public static String encryptBellaso(String plainText, String bellasoStr)

{

//encrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<plainText.length())

{

bellasoStr+=bellasoStr.substring(0,(plainText.length()-bellasoStr.length()));

}

//encryption

for(int i=0;i<plainText.length();i++)

{

char c=(char)Wrap_around((int)plainText.charAt(i)+(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

/*

This method decrypts a string according to the Bellaso Cipher. Each character

in encryptedText is replaced by the character corresponding to the character in

bellasoStr, which is repeated to correspond to the length of plainText. This is

the inverse of the encryptBellaso method. The parameter encryptedText is the

encrypted string to be decrypted, and bellasoStr is the string used to encrypt

the original text. The method returns the original plain text string.*/

public static String decryptBellaso(String encryptedText, String bellasoStr)

{

//decrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<encryptedText.length())

{

bellasoStr+=bellasoStr.substring(0,(encryptedText.length()-bellasoStr.length()));

}

//decryption

for(int i=0;i<encryptedText.length();i++)

{

char c=(char)Wrap_around((int)encryptedText.charAt(i)-(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

}

6 0
3 years ago
Mario is giving an informative presentation about methods for analyzing big datasets. He starts with the very basics, like what
Natasha2012 [34]

Answer:

Audience knowledge level

Explanation:

The Key issue that Mario failed to consider when preparing for her presentation is known as Audience knowledge level.  

Because Audience knowledge level comprises educating your audience with extensive information about the topic been presented. she actually tried in doing this but she was educating/presenting to the wrong audience ( People who are more knowledgeable than her on the topic ). she should have considered presenting a topic slightly different in order to motivate the audience.

3 0
3 years ago
How many mb are in a gb?
frosja888 [35]

Answer:

1000 megabytes are in a gigabyte

Explanation:

3 0
2 years ago
Using Karnaugh maps, simplify the following Boolean function:
Flura [38]

Answer:

F(a,b,c,d)=b'c' + a'cd' + ab'd'.

Explanation:

The image of the corresponding k-map is attached to this answer please refer it.By the sop given in the question the k-map is formed.There are 3 groups formed 1 group of four 1's and 2 groups of 2 1's.Hence there are three sop and the sop is reduced from the previous SOP.

8 0
3 years ago
You connect your computer to a wireless network available at the local library. You find that you can access all of the websites
leva [86]

Answer:

There must be a  proxy server that is not allowing access to websites

Explanation:

A wireless network facility provided in colleges, institutions, or libraries is secured with a proxy server to filter websites so that users can use the network facility for a definite purpose. Thus, that proxy server is not allowing access to all of the websites to the user on the internet except for two.

4 0
3 years ago
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