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Roman55 [17]
4 years ago
5

Please answers quick ,whats an inequality?

Mathematics
2 answers:
dangina [55]4 years ago
8 0
An inequality is a relation that makes a non-equal comparison between two numbers or other mathematical expressions. It’s mostly used to compare 2 numbers on the number line by sizes.
Deffense [45]4 years ago
8 0

Answer:

Step-by-step explanation:

inequality is a equation with |x|

a inequality equation is like this..

|x|>7

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A school buys games for 6 classrooms. It buys 3 board games, 4 puzzles, and 1 video for each classroom. How many games dose the
AlexFokin [52]

Answer:

42

Step-by-step explanation:

4+3=7

7x6 = 42

7 0
3 years ago
Suppose <br> f '(x) = xe^−x^2
iogann1982 [59]
<h3>Answers:</h3>
  • (a) The function is increasing on the interval (0, infinity)
  • (b) The function is decreasing on the interval (-infinity, 0)

=======================================================

Explanation:

You should find that the derivative is entirely negative whenever x < 0. This suggests that the function f(x) is decreasing on this interval. So that takes care of part (b).

The interval x < 0 is the same as -infinity < x < 0 which then translates to the interval notation (-infinity, 0)

Similarly, you should find that the derivative is positive when x > 0. So the function is increasing on the interval (0, infinity)

6 0
3 years ago
Math drawing geometry help.. please x.x ill reward thank you im stuck on this too
Alisiya [41]

a=(4,1) b=(4,3) c=(8,2) d=(8,0) i think i havent done these in a while

6 0
3 years ago
(4.04 MC)
aev [14]

The equation of a linear function: y = mx + b

x = y - 3 → y - 3 = x      <em>add 3 to both sides</em>

y = x + 3     <em>it's a linear function!</em>


y = x³ + 2 NOT, because we have x³

y = 6x² NOT, because we have x²

y = 2/(3x) NOT, because x is in denominator.

7 0
3 years ago
Read 2 more answers
At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37
monitta

Answer:

Half-life of the goo is 49.5 minutes

G(t)= 300e^{-0.014t}

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let M_0\,,\,M_f denotes initial and final mass.

M_0=300\,\,grams\,,\,M_f=37.5\,\,grams

According to exponential decay,

\ln \left ( \frac{M_f}{M_0} \right )=-kt

Here, t denotes time and k denotes decay constant.

\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014

So, half-life of the goo in minutes is calculated as follows:

\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes

Half-life of the goo is 49.5 minutes

\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}

So,

G(t)= M_f=M_0e^{-kt}

Put M_0=300\,\,grams\,,\,k=0.014

G(t)= 300e^{-0.014t}

Put t = 32 minutes

G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams

7 0
3 years ago
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