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larisa86 [58]
3 years ago
15

Solve |x| = -15 { } {-15} {-15, 15}

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0
The absolute value is always non-negative.
|x|=-15\\
x\in \{\}
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77julia77 [94]
50,000 ÷ 2,500 = 20 bolts
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Hope this helps!
4 0
4 years ago
Fred and Frank play a game. Fred picks an even number X and asks Frank to add all even numbers between 0 and X (inclusive) as fa
TiliK225 [7]

Answer:

The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2

The rule of arithmetic sequence = a + d(n - 1)

Where a is the first term and n is the number of terms

So, for the even numbers between 0 and X

The first term = a = 0

d = 2

So, we need to find n at the last term which is X

∴ X = 0 + 2 ( n -1 )

∴ n - 1 = X/2

∴ n = X/2 + 1

The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)

Substitute with a and d and X

So, the sum = (n/2) * (2*0 + (n−1)*2)

                   = (n/2) * ((n−1)*2)

                   = n(n-1)

                   = (X/2 + 1) * (X/2)

                   = X/2 by (X/2 + 1)

So, The quick way to add all even numbers between 0 and X always works.

8 0
4 years ago
If RS = 2x + 5, RU = x + 8, and TU = x + 16, what is the value of x?
timofeeve [1]
Opposite sides of a parallelogram are congruent. Therefore, RS = TU. 

<span>2x+5 = x + 16. </span>

<span>x = 11

</span>
8 0
4 years ago
What set would no longer be a A function if the ordered pair(5,3) was added
Delicious77 [7]
The answer is D because a function means for every input  you get exactly one output so
for every x you get one y
in D there is a coordinate (5,2) meaning that if you put in 5 for x you get 2 for y

but the new ordered pair also  has 5 for x but has a difarent y value.  this violates the definition of a funciton
4 0
3 years ago
Read 2 more answers
What factor of the number 144is neither prime nor composite
butalik [34]
There isn't a factor that isn't prime or composite.
6 0
3 years ago
Read 2 more answers
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