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Mathematics

1 answer:

Brums [2.3K]3 years ago

3 0

Answer:

served a greater variety of ages and then range

hope it helped!

Step-by-step explanation:

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Sunny_sXe [5.5K]

Ok thanks for letting me know !

5 0

3 years ago

The value of a collector’s item is expected to increase exponentially each year. The item is purchased for $500. After 2 years,

Andreyy89

Y = 500(1 + r)^x; where r is the rate and x is the number of years.
500(1 + r)^2 = 551.25
(1 + r)^2 = 551.25/500 = 1.1025
1 + r = sqrt(1.1025) = 1.05

Therefore, the equation that represents y, the value of the item after x years is
y = 500(1.05)^x

7 0

4 years ago

Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion do

V125BC [204]

Answer:

Step-by-step explanation:

It is given that

$\Delta=\begin{vmatrix}3&0&3\\2 &3&3\\0 &4&-2\end{vmatrix}$

By cofactor expansion across the first row, we get

$\Delta=a_{11}C_{11}+a_{12}C_{12}+a_{13}C_{13}$

$\Delta=3\left[(-1)^{1+1}\begin{vmatrix}3&3\\4&-2\end{vmatrix}\right]+0\left[(-1)^{1+2}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{1+3}\begin{vmatrix}2&3\\0&4\end{vmatrix}\right]$

$\Delta=3\left[-18\right]+0\left[(-1)(-4)\right]+3\left[8\right]$

$\Delta=-54+0+24$

$\Delta=-30$

Therefore, the value of determinant is -30.

By cofactor expansion across the second column, we get

$\Delta=a_{12}C_{12}+a_{22}C_{22}+a_{32}C_{32}$

$\Delta=0\left[(-1)^{2+1}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{2+2}\begin{vmatrix}3&3\\0&-2\end{vmatrix}\right]+4\left[(-1)^{3+2}\begin{vmatrix}3&3\\2&3\end{vmatrix}\right]$