6(2)+3y=15
12+3y=15
-12 -12
3y=3
3y/3 3/3
y=1
6(5)+3y=15
30+3y=15
-30 -30
3y=-15
3y/3 -15/3
y= -5
5x - 3y = 11 ⇒ 5x - 3y = 11 ⇒ 5x - 3y = 11
x - 2y = 2 ⇒ -5(x - 3y) = 2 ⇒ <u>-5x + 15y = 2</u>
<u>12y</u> = <u>13</u>
12 12
y = 1 1/12
5x - 3(1 1/12) = 11
5x - 3 1/4 = 11
<u> +3 1/4 +3 1/4</u>
<u> 5x</u> = <u>14 1/4</u>
5 5
x = 2 17/20
(x, y) = (2 17/20, 1 1/12)
From the markings on the diagram, we can tell E is the midpoint of BC and <u>D</u> is the midpoint of AC. We can apply the <u>triangle midsegment theorem</u>: ED = ½BA. Substituting in the expressions for the lengths and solving for x, we get x = <u>5</u>. Now, since BE = x, then BC = <u>10</u>.
<h3>What is
triangle midpoint theorem?</h3>
Triangle midpoint theorem states that the line segment which joins the midpoints of two (2) sides of a triangle is parallel to the third side, and it's congruent to one-half of the third side.
By applying the triangle midpoint theorem, we can find the value of x:
ED = ½BA
x + 2 = ½(4x - 6)
2x + 4 = 4x - 6
4x - 2x = 6 + 4
2x = 10
x = 10/2
x = 5.
BC = x + x
BC = 5 + 5
BC = 10.
Read more on triangle midpoint theorem here: brainly.com/question/16047906
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Itshould be 6/11 sorry if it’s wrongg
Answer:
Step-by-step explanation:
3ab + 7a² + 2b² - (7a² - 4ab + 2b²) = 3ab + 7a² + 2b² - 7a² + 4ab - 2b²
Now combine like term. Like terms have same variable with same power.
= <u>3ab + 4ab</u> <u>+ 7a² - 7a²</u> + <u>2b² - 2b²</u>
= 7ab