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PolarNik [594]
3 years ago
14

Flying against the wind, an airplane travels 4560 kilometers in 6 hours. Flying with the wind, the same plane travels 3720 kilom

eters in 3 hours. What is the rate of the plane in still air and what is the rate of the wind?
Mathematics
1 answer:
Flura [38]3 years ago
7 0

Answer:

The speed rate of the plane in still air is 1006.67 km/h

The speed rate of the wind is 246.67 km/h

Step-by-step explanation:

To answer the question, we let the speed of the plane in still air = x  km/h

Let the speed of the wind = y km/h

Therefore,

4560/(x - y) = 6 hours and

3720/(x + y) = 3 hours

4560 = 6·x - 6·y.........(1)

3720 = 3·x + 3·y ........(2)

Multiplying equation (2) by 2 and add to (1) gives

12080 = 12·x

x = 12080/12 = 1006\frac{2}{3} km/h

Substituting the value of x in (1) gives

4560 = 6040 - 6·y

6·y = 1480

y = 1480/6 =  246\frac{2}{3}

The speed rate of the plane in still air = 1006.67 km/h

The speed rate of the wind = 246.67 km/h.

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Which is perpendicular to the line y=-3x-8y
atroni [7]

Answer:

I believe the answer is y = -7/3x

Step-by-step explanation:

When you rearrange the equation, y = -3x - 8y, you will get -7y = -3x.

We want the equation to be equal to y by itself. So we divide -7 from both sides, giving us the equation y = 3/7x.

The graph that is perpendicular to y = 3/7x is it's reciprocal: y = -7/3x

4 0
3 years ago
Read 2 more answers
The tree in Greg's backyard is 8.7m high. How high is it in centimeters?
serious [3.7K]

it is 870 cm tall

(That is the correct answer)

8 0
4 years ago
estimate the number of first-year students at an assembly meeting. He surveys 60 students and finds that 24 of them are first-ye
bogdanovich [222]

Answer:

The values needed to calculate a confidence interval at the 95% confidence level are z = 1.96, n = 60, \pi = \frac{24}{60} = 0.4

The 95% confidence interval for the proportion of first-year students at an assembly meeting is (0.276, 0.524).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 60, \pi = \frac{24}{60} = 0.4

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The values needed to calculate a confidence interval at the 95% confidence level are z = 1.96, n = 60, \pi = \frac{24}{60} = 0.4

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.4*0.6}{60}} = 0.276

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.4*0.6}{60}} = 0.524

The 95% confidence interval for the proportion of first-year students at an assembly meeting is (0.276, 0.524).

6 0
3 years ago
I need help with this answer please
Elis [28]

Answer:

Y= x+2

Step-by-step explanation:

The x value is always adding 2 to get the y value

1+2=3

2+2=4

3+2=5

4+2=6

5+2=7

Therefore your answer is y = x + 2

Hope this helps!

5 0
4 years ago
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3. A snowmobile manufacturer claims that its newest model is 15% lighter than last year’s model. If this year’s model weighs 799
mr_godi [17]
We can calculate this by setting up a proportion:
x/100=799/85 so we multiply 799 by 100 receiving 79900 then we divide 79900 by 85 and receive 940. So last years model weighs 940 lb.
4 0
3 years ago
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