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Answer:
The answer is below
Explanation:
The amount of power dissipated by a processor is given by the formula:
P = fCV²
Where f = clock rate, C = capacitance and V = Voltage
For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:
P(old) = fCV²
For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:
P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor
Hence, the new processor is 1.728 times (72.8% more) the power of the old processor
<span>Dragging or sizing affects only a "Selected Object." For example, an image, you need to click the image in order for you to select that image. The image is considered as an object. From the time you click on the picture, there are points visible where you can click and drag upon it nor resize.</span>
Answer:
The answer is weak, Have a nice day! :)
Explanation:
D) weak
2^(32-20) - one for the network number - one for the broadcast address = 4,094
