Answer:
printStars(35);
Explanation:
public class Question {
public static void main(String args[]) {
printStars(35);
}
public static void printStars(int numberOfStars){
for(int i = 1; i <= numberOfStars; i++){
System.out.print("*");
}
System.out.print("\n");
}
}
Answer:
non-volatile and persistent in nature
Answer:
Consider the following code.
Explanation:
save the following code in read_and_interp.m
function X = read_and_interp(s)
[m, n] = size(s);
X = zeros(m, 1);
for i = 1:m
if(str2num(s(i, 2:5)) == 9999)
% compute value based on previous and next entries in s array
% s(i, 2:5) retrieves columns 2-5 in ith row
X(i,1) = (str2num(s(i-1 ,2:5)) + str2num(s(i+1,2:5)))/2;
else
X(i,1) = str2num(s(i,2:5));
end
end
end
======================
Now you can use teh function as shown below
s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];
read_and_interp(s)
output
ans =
96.000
114.000
109.500
105.000
112.000
Answer:
To sum up all the advantages of using the relational database over any other type of database, a relational database helps in maintaining the data integrity, data accuracy, reduces data redundancy to minimum or zero, data scalability, data flexibility and facilitates makes it easy to implement security methods.
Explanation:
I hope it helps you..
Just correct me if I'm wrong..
The answer is already given at the end of the question; solely by the magnitude or severity of expected harm
When assessing risks of harm associated with participation in a research study, the probability of harm and the risk of the severity of harm are two distinctive elements of risk that must be considered. In probability of harm, the fact that not all possible harms are equally probable should be considered. How these two elements occur is a crucial factor in determining the level of risk of harm in a study. Given the sensitivity of the information in the case scenario above, the probability that an individual subject could be identified is low while the magnitude of the possible risk of harm is high.
