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3 years ago

What is the range of possible sizes for side x? 4.0 2.7

Computers and Technology

1 answer:

Aleksandr-060686 [28]3 years ago

5 0

Answer:

$1.3< x < 6.7$ is the correct answer to the given question .

Explanation:

In this question the figure is missing We have attached the figure kindly find it .

Now coming to the answer

With the help of Triangle Inequality Theorem.

The triangle Inequality theorem saying that the total of a sizes of either side of a triangle is larger than the size of a third side

Consider that x be the measurement of the 3rd side triangle

Now apply the theorem of Inequality

(1 )

$4.0+2.7 > x\\\\6.7 > x$

Update the equation so it will written like that

$x< 6.7 \ units$

(2)

Again with the help of triangle Inequality theorem

$x+2.7 > 4.0\ \\x\ > 4.0-2.7\ \\x\ > 1.3\ units$

Hence the possible ranges of the size is $(1.3 ,6.7)$

Therefore the answer is 1.3< x < 6.7

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Ira Lisetskai [31]

Answer:

Explanation:

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3 years ago

Which of the following is a high-speed network dedicated to storage that connects different kinds of storage devices, such as ta

Montano1993 [528]

Answer:

SAN

Explanation:

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3 years ago

What is the Moore's law

Nadya [2.5K]

Answer:

Hi, in the law of Moore we can express aproxitmaly for each <em>two years</em> is duplicated the number of transitors in a microprocessor.

Explanation:

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I hope it's help you.

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3 years ago

Write the following function without using the C++ string class or any functions in the standard library, including strlen(). Yo

dolphi86 [110]

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){

int lenstr1=0;

while(str1[lenstr1] != '\0'){ lenstr1++; }

int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

while (str2[index] != '\0'){

if (str1[i] == str2[index]){

retIndex=1;

break; }

else{ retIndex=0; }

index++; }

if (retIndex == 0){ return i; }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){ lenstr1++; }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

while (str2[index] != '\0'){

If current element of str2 and str1 are the same

if (str1[i] == str2[index]){

Set the returned index to 1

retIndex=1;

Then exit the loop

break; }

If otherwise, set the returned index to 0

else{ retIndex=0; }

Increase index by 1

index++; }

This returns the calculated returned index; if no matching is found, it returns -1

if (retIndex == 0){ return i; }else{return -1;}}

}

4 0

3 years ago

If several programs or apps are running simultaneously, your computer or device might use up its

kirill [66]

Answer: I am pretty sure it's RAM

Explanation:

I'm not 100% positive bc I haven't gotten my scores back yet but I think that's it.

7 0

3 years ago