Something like this?
h1 = int(input())
m1 = int(input())
s1 = int(input())
h2 = int(input())
m2 = int(input())
s2 = int(input())
s = h2*3600 + m2*60 + s2 - (h1*3600 + m1*60 + s1)
print(s)
Answer:
The best answer is "B"
xfs_fsr
Explanation:
The is a typical format of the command to use:
xfs_metadump -o /dev/sdb1 /reviewxfs
let's say they catch-up to each other after t hour.
so
in t hour distance travelled by Renee
d = speed × time = 50t
in t hour distance travelled by Kim
d = speed × time = 60(t-1) + 0×1 = 60(t-1)
Note: here kim didn't covered any distance in first hour and in rest t-1 hour it travelled all distance
now.as distance travelled by both is same so
60(t-1) = 50t
60t -60 = 50t
adding 60 both sides
60t = 50t+60
subtracting 50t both sides
60t -50t = 50t+60 - 50t
10t = 60
dividing by 10 both sides
t = 60/10 = 6
so in 6 hour both will catch-up to each other
E) both C and D
Erro handling and execution paths
Flip the laptop over, take off the screws that hold the frame together. Flip it back, take off the top plate. Then, slide the keyboard back in. Replace the frame, and then rescrew the screws. Replace the back side after.
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