The linear equation y = -6x + 2; -12x - 2y = -4 has no solution
<h3>Linear equation</h3>
y = -6x + 2
-12x - 2y = -4
- Substitute y = -6x + 2 into (2)
-12x - 2y = -4
-12x - 2(-6x + 2) = -4
-12x + 12x -4 = -4
-12x + 12x = - 4 + 4
0 = 0
y = -6x + 2
y - 2 = -6x
x = (y - 2) / -6
-12x - 2y = -4
-12(y- 2)/ 6 - 2y = -4
(-12y + 24) / 6 - 2y = -4
-2y + 4 - 2y = 4
0 = 0
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Answers:
Diameter - B)
Circumference - F)
Radius - C) or <span>E)*</span>
Secant - E) or C)*
Concentric circles - D)
Arc - A)
* Please, note that you described option C and option E with the same exact words. One of the two is supposed to be different.
Let's see the definition of each term of the list on the left in order to find the right description:
<em>Diameter</em> = any segment connecting two points on a circle passing through its center. Therefore, the correct description is B) a segment between two points on a circle that passes through its center.
<em>Circumference</em> = length of the distance around the circle (it's a sort of perimeter of the circle). Therefore, the correct description is F) the distance around a circle
<em>Radius</em> = constant distance from the center to any point on the circle. Therefore, the correct description is C/E) a line segment connecting the center C and a point B on the circle.
<em>Secant</em> = a<span> line that intersects a circle at any two points. Therefore the correct description is </span>E/C) Circle A and a line segment connecting the points B and C which are both on the circle.
<em>Concentric circles</em> = two circles positioned such as the center of the first one coincides with the center of the second one. Therefore the correct description is D) Two circles that share the same center.
<em>Arc</em> = part of the curve along the perimeter of a circle. Therefore, the correct description is A) a piece of the circumference of a circle.
The graph is a circle, centered at the origin, with radius=4.
We know that we can write the equation of a circle with radius r and center (a,b) as :

.
Thus, substituting (a, b) with (0, 0) and r with 4, we have:

.
The solutions of this equation are all the points forming the circle shown in the picture. The solutions of this equation are still the same even if we multiply both sides of the equation by 2, because rewriting the equation as:

,
we would still have the same roots.
Thus, the equation of the circle can be written as :

.
Answer: B
Answer:
y= -3x+2
Step-by-step explanation:
