Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24
Solve for y like the top equation:
2y = -4ax + 11
2y/2 = -4ax/2 + 11/2
y = -2ax + 11/2
Answer:
A'
Step-by-step explanation:
It is A' because they are corresponding angles, it is the same exact shape it has just been translated to a different area of the graphic plane.
If my answer is incorrect, please notify me and I'll assess what it was that I did wrong.