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3 years ago

32/96 in its simplest form

2 answers:

5 0

The answer is 1/3.
To get to this conclusion you must halve both the numerator and the denominator until you reach a point where each number can no longer be halved.
32/96
16/48
8/24
4/12
2/6
1/3

taurus [48]3 years ago

5 0

32/96
= (32/32) / (96/32)
= 1/3

32/96 in its simplest form is 1/3~

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Can someone please give me the (Answers) to this? ... please ...<br><br> I need help….

bezimeni [28]

Answer:

see explanation

Step-by-step explanation:

2 chords intersecting inside a circle , then the product of the parts of one chord is equal to the product of the parts of the other chord.

BE × ED = AE × CE , that is

10 × 3x = 12(2x + 1) ← distribute parenthesis by 12

30x = 24x + 12 ( subtract 24x from both sides )

6x = 12 ( divide both sides by 6 )

x = 2

then

ED = 3X = 3(2) = 6

RJ × JP = SJ × JQ , that is

6 × 3x = 4(4x + 1) ← distribute parenthesis by 4

18x = 16x + 4 ( subtract 16x from both sides )

2x = 4 ( divide both sides by 2 )

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2 years ago

This type of member variable may be accessed before any objects of the class have been created.

alina1380 [7]

Answer:

d. static

Step-by-step explanation:

This is a question about Java programming.

A class contains information about it's members(objects). Private, public or inline variables must be related to an object, that is, an object has to be created before the variable is acessed.

Static variables, otherwise, may pertain to the class, and not to the object, that is, and thus, the correct answer is given by option d.

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3 years ago

Which is greater 3/4 or 11/16 and how can you be sure

ICE Princess25 [194]

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4 years ago

Read 2 more answers

TOY has coordinates T (-3, 4), O (-4, 1) and Y (-2, 3). a translation maps point T to T' (-1, 1). find the coordinates of O' and

NeX [460]

Answer:

Answer: The correct option is (A) O' (−2, −2); Y' (0, 0).

Step-by-step explanation: Given that the co-ordinates of the vertices of ΔTOY are T(−3, 4), O (−4, 1), and Y (−2, 3). A translation maps point T to T' (−1, 1).

We are to find the co-ordinates of the points O' and Y'.

The given transformation from T to T' is

T(−3, 4) ⇒ T' (−1, 1).

Let, (−3 + x, 4 + y) = (-1, 1).

So,

and

That is, the transformation rule is

(a, b) ⇒ (a+2, b-3).

Therefore,

co-ordinates of O' are (-4+2, 1-3) = (-2, -2),

and

co-ordinates of Y' are (-2+2, 3-3) = (0, 0).

Thus, the required co-ordinates of O' and Y' are (-2, -2) and (0, 0) respectively.

Option (A) is correct.

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