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yawa3891 [41]
3 years ago
6

The volume of a rectangular box can be found using the formula lwh where l represents the length, w represents the width, and h

represents the height of the box. What is the volume of a box with the following dimensions?
I = 4 centimeters
W= 5 centimeters
H=6 centimeters
Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

120 cm^3

Step-by-step explanation:

volume = lwh

I = 4 centimeters  

w = 5 centimeters  

h = 6 centimeters

volume = (4 cm)(5 cm)(6 cm)

volume = 120 cm^3

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Sergio [31]

Answer:

m∠x = 98°

Step-by-step explanation:

Step 1: Find the supplementary angle in the triangle

180 - (53 + 45) = 82

Step 2: Use Supplementary Angles to solve for <em>x</em>

180 - 82 = 98°

6 0
3 years ago
Subtracting Factions 1 2/3 - 2 1/3=
skad [1K]

Answer:

-2/3

Step-by-step explanation:

1 2/3 - 2 1/3

5/3 - 2 1/3

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-2/3

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Find the number of real number solutions for the equation x^2-3+8=0
svlad2 [7]
Find value of determinant.
The determinant is a term that is inside a square root and part of the quadratic formula used for solving quadratic equations.
Let determinant be 'd'.
If d >0, Then there are 2 real solutions
If d = 0, Then there is only 1 real solutions
If d < 0, Then there are 0 real solutions but 2 imaginary solutions

d = b^2 - 4ac

For this problem, the coefficients are:
a = 1, b = -3, c = 8

d = (-3)^2 - 4(1)(8)

d = 9 -32 = -23

d is less than 0, therefore there are 0 real solutions and 2 imaginary solutions.

This is true because you cannot take square root of a negative number.



5 0
3 years ago
Find the missing length <br> . Leave your answers in simplest radical form
Eddi Din [679]

Use Pythagorean theorem:

x^2+5^2=(\sqrt{122})^2\\\\x^2+25=122\qquad\text{subtract 25 from both sides}\\\\x^2=97\to x=\sqrt{97}

4 0
2 years ago
A motorboat travels 220 kilometers in 4 hours going upstream. It travels 260 kilometers going downstream in the same amount of t
aliya0001 [1]

Answer:    The rate of boat is 60 kmh.

                  The rate of current is 5 kmh.

Step-by-step explanation:

Alright, lets get started.

Suppose the rate of boat in still water is : b kmh

Suppose the rate of current is  : c kmh

When the boat is going upstream, the relative speed will be : (b-c)

When the boat is going downstream, the relative speed will be: (b+c)

Boat travels 220 kilometers in 4 hours going upstream.

speed=\frac{distance}{time}

(b-c)=\frac{220}{4}   .................. equation (1)

It travels 260 kilometers going downstream in the same amount of time.

(b+c)=\frac{260}{4}  ................... equation (2)

Adding equation 1 and 2

b-c+b+c=\frac{220}{4}+\frac{260}{4}

2b=\frac{480}{4}

2b=120

b=60

Plugging the value of b as 60 in equation 2

60+c=\frac{260}{4}

60+c=65

c=5

Hence the rate of boat is 60 kmh.

Hence the rate of current is 5 kmh.

Hope it will help :)

6 0
3 years ago
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