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mixas84 [53]
2 years ago
15

a total of 695 tickets were sold for the school play. They were either adult or student tickets. There was 55 fewer students tic

kets sold than adult tickets. How many adult tickets were sold?​
Mathematics
1 answer:
FinnZ [79.3K]2 years ago
4 0

Answer:

375 + 320

Step-by-step explanation:

375 adult

320 students

equals 395

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The miles per hour is 84 kilometers per 60 minutes (7:5 ratio) so if we take seven kilometers times the ratio 5/7 we get 5 minutes
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3 years ago
Gary drove to the park at a rate of 50 miles per hour if it took him 2.5 hours to get from his house to the park how far away is
Marina86 [1]

Answer:

The distance of the park from the Gary's house is 125 miles.

Step-by-step explanation:

Speed of Gary = 50 miles/hour

Time taken by Gary to reach the park from his house = 2.5 hours

Now, we know that,

Distance travelled = speed × time

So,  distance between park and Gary's house = speed × time

= 50 × 2.5

= 125 miles

So, the park is 125 miles away from the Gary's house.

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3 years ago
Tiana compares the length of a name on a nameplate to the number of letters in the name. She draws the scatterplot below, and th
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Answer:

3

Step-by-step explanation:

Edge 2020

8 0
3 years ago
Read 2 more answers
Estimate the perimeter and the area of the shaded figure to the nearest tenth.<br> -Please help me-
Crank

Answer:

Perimeter = 12+4pi

Area = 16+8pi

Step-by-step explanation:

Description of the assumed shape:

A rectangle 2 x 8 superimposed on a semi-circle of radius 4.

Perimeter:

P = 2+8+2+(4)(pi) = 12+4pi

Area :

A = 2*8 +(pi)4^2/2 = 16 + 8pi

3 0
3 years ago
There are 50 deer in a particular
olchik [2.2K]

answered

There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents

the number of deer y in that forest after x months? Round to the nearest thousandth.

1

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dribeiro

Ace

697 answers

561.4K people helped

Answer:

The expression that represents the number of deer in the forest is

y(x) = 50*(1.013)^x

Step-by-step explanation:

Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:

y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625

y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258

y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898

This keeps going as the time goes on, so we can model this growth with the equation:

y(x) = 50*(1 - 0.15/12)^(x)

y(x) = 50*(1.013)^x

8 0
2 years ago
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