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Daniel [21]
3 years ago
12

I need some assistance on finding the arc measure

Mathematics
1 answer:
Kitty [74]3 years ago
7 0
D to B =180
B to D=180
D to C =19
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Which ordered pair is a solution to the equation 2x - 4y = 18?
weqwewe [10]
(11,1) because if you plug in x and y this answer is the only one that gives you 18 in the end
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How many buttons are found on a simple calculator? It is measured in the _____.
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Answer: The minimum is 16, probably arranged in 4 rows of 4 buttons.


Step-by-step explanation: just grab a calculator lol



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What is the slope of a line parallel to the line whose equation is3x−4y=8?
xxTIMURxx [149]

The slope of the parallel line is 3/4

<h3>How to determine the slope?</h3>

The equation is given as:

3x - 4y = 8

Rewrite as:

4y = 3x - 8

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y = 3x/4 -  2

A linear equation is represented as:

y = mx + b

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Parallel lines have equal slope

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Read more about slope at:

brainly.com/question/3493733

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7 0
1 year ago
Pleaseee helppp with thissss asapppp
Natasha2012 [34]

As we know that the standard equation of circle is {\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}} , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

{:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}

{:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}

{:\implies \quad \sf 9+16=r^{2}}

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

{:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

8 0
2 years ago
AB is the angle bisector of CAD. Solve for the missing variable?
Alika [10]

Answer:

x=8^\circ

Step-by-step explanation:

A bisector is the line that divides an angle (which in this case is \angle CAD) exactly in half. Therefore, \angle CAB = \angle BAD and as such we can solve for x:

\angle CAB &= \angle BAD\\33^\circ &= 4x + 1^\circ\\4x = 32^\circ\\x = 8^\circ

and we are done.

4 0
2 years ago
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