To solve the problem, let x be the number of monthly quota of problems. Below is the list of the problems solved each week,
1st week - 0.25x
2nd week - 1.10(0.25x)
3rd week - 0.6(0.25x + 1.10(0.25x))
4th week - 320
To solve for the monthly quota, equate the sum of all the problems solved to x and determine its value. Thus, the students solved 2000 problems all in all.
78,369 and i dont get what the four step is, next time can you be a little more specific. PLEASE
The denominator must be the same, so just think of the LEAST COMMON MULTIPLE, The LCM here is 8, because you can multiply 4 by 2 to get 8.
so when you multiply, you multiply both on the top and on the bottom, so this would be:
3 x 2 / 4 x 2 = 6 / 8
Now you can add or subtract: 6/8 - 1/8 = 5/8
Answer:
bro it had been decreased
<h3>so total had been decreased is</h3><h3> (4,000,000-2,900,000)=1,100,000</h3>