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crimeas [40]
2 years ago
14

How do I solve (7-6i)(-8+3i)?

Mathematics
2 answers:
Alekssandra [29.7K]2 years ago
6 0
I = {2.666666667, 1.166666667
konstantin123 [22]2 years ago
5 0
Solution step by step

(7-6i)(-8+3i)
=7×(-8)+7×3i-6i×(-8)-6i×3i
=-56+21i+48i+18i^2
=-56+69i-18×(-1)
=-56+69i+18
=-38+39i
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Answer:

24

Step-by-step explanation:

(-4) -6? well it equals 24 because a negative plus a negative equals a positive.

Hope my answer has helped you! If not i'm sorry.

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try this link

Step-by-step explanation:

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3 years ago
For all values of x
Yuliya22 [10]

Answer:

A.) gf(x) = 3x^2 + 12x + 9

B.) g'(x) = 2

Step-by-step explanation:

A.) The two given functions are:

f(x) = (x + 2)^2 and g(x) = 3(x - 1)

Open the bracket of the two functions

f(x) = (x + 2)^2

f(x) = x^2 + 2x + 2x + 4

f(x) = x^2 + 4x + 4

and

g(x) = 3(x - 1)

g(x) = 3x - 3

To find gf(x), substitute f(x) for x in g(x)

gf(x) = 3( x^2 + 4x + 4 ) - 3

gf(x) = 3x^2 + 12x + 12 - 3

gf(x) = 3x^2 + 12x + 9

Where

a = 3, b = 12, c = 9

B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)

To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula

Y = 3x + 3

X = 3y + 3

Make y the subject of formula

3y = x - 3

Y = x/3 - 3/3

Y = x/3 - 1

Therefore, g'(x) = x/3 - 1

For g'(12), substitute 12 for x in g' (x)

g'(x) = 12/4 - 1

g'(x) = 3 - 1

g'(x) = 2.

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2 years ago
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3 years ago
Mandy built a pyramid for her project on Egypt with a volume of 483
emmainna [20.7K]

Answer

We have,

Volume of pyramid = 4834 in³

Base area of the pyramid = ?

Assuming height of the pyramid = 20 in

We know that

Volume of pyramid =\dfrac{hlw}{3}  

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Hence, area of the base of the pyramid is equal to 725.1 in².

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3 years ago
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