Question

What is the terminal point of the vector \mathbf{a}=\left<5,2\right> based at P=\left(4,1\right)?

Answer 1

Answer:

The terminal point of the given vector is (9,3).

Step-by-step explanation:

The given vector is

$\mathbf{a}=\left$

If initial point is $P(x_1,y_1)$ and terminal point is $Q(x_2,y_2)$, then vector PQ is defined as

$\overrightarrow{PQ}=$

Initial point is P=(4,1). Let (a,b) are the coordinates of terminal point.

$=$

On comparing both sides we get

$a-4=5\Rightarrow a=5+4\Rightarrow a=9$

$b-1=2\Rightarrow b=2+1\Rightarrow b=3$

Therefore, the terminal point of the given vector is (9,3).