B C 2 Choose the wrong name for this angle: 2 В) с

LiRa [457]

Answer:

134 degrees

Step-by-step explanation:

Line PQS is 180 degrees. That being said, the addition of <PQR and <SQR equal 180 degrees.

Now you need to set up an equation to find out what angle PQR is. Since there is an X, you need to solve for X. The equation looks like this:

$(3x+5) + (x+3) = 180$

Solve for x

$(3x+5) + (x+3) = 180\\4x+8=180\\4x=172\\x=43$

Now plug in 43 where you see x. For this question, you only need to focus on (3x+5)

3(43) + 5 = 134

m<PQR = 134°

Do this every, single, time when you see these questions. Remember that line PQS is 180 degrees, and both of those angles are equal to 180 degrees.

If you want to check if this is true, plug in 43 into our equation we made to see if it equals 180 degrees. If it doesn't equal 180, your equation is incorrect.

3(43)+5+43+3 = 180

134 + 46 = 180

180 = 180 ✅

4 0

2 years ago

How many centimeters are there in 1/5 of an inch

Lynna [10]

Answer:

0.508

Step-by-step explanation:

4 0

3 years ago

Charlie used a regression calculator to generate the equation f(x) = –0.15x + 20.1 for the ordered pairs (2, 15), (4, 21), (6, 2

aivan3 [116]

Answer: The r-value for the linear function related to the ordered pairs is very close to zero, so it is not a good representation of the data. A quadratic model would better represent the data because there is a turning point within the data set. The data increases then decreases, which is what the graph of a quadratic does.

8 0

2 years ago

Read 2 more answers

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2 Express answer as a common fraction. Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$

3 0

3 years ago

Round yo the nearest hundred plz it’s not much!!!!!!!!!

natita [175]

A is the answer of not I’m sorry for that

7 0

3 years ago