Function f is defined by f(x)=2x-7 find f(3)

Can someone help me solve this and explain step by step algebraically <br> 1/8x+1/4y=2

mote1985 [20]

Answer:

$x=16-2y$

Step-by-step explanation:

$\mathrm{Subtract\:}\frac{1}{4}y\mathrm{\:from\:both\:sides}$

$\frac{1}{8}x+\frac{1}{4}y-\frac{1}{4}y=2-\frac{1}{4}y$

$\mathrm{Simplify}$

$\frac{1}{8}x=2-\frac{1}{4}y$

$\mathrm{Multiply\:both\:sides\:by\:}8$

$8\cdot \frac{1}{8}x=8\cdot \:2-8\cdot \frac{1}{4}y$

$\mathrm{Simplify}$

$x=16-2y$

Final Answer: $x=16-2y$

6 0

3 years ago

If the ration of bananas to apples was 9 to 15. If there were twelve bananas, how many total pieces of fruits was there

KiRa [710]

Answer:

IM not too sure but i think 30

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Lizzy has 6.5 hours to tutor 4 students and spend 1.5 hours in a lab. She plans to tutor each student the same amount of time. T

olchik [2.2K]

Not really sure whats up with that inequality but she can't, if she has to spend 1.5 hours in a lab that leaves her with 5 hours. 5/4 is 1.25, so no, she can only spend 1.25 hours with each student.

8 0

4 years ago

The probability that a car has a certain factory defect is 825. The probability that a car has a certain factory defect and need

ipn [44]

Answer:

90.91% probability that a car needs an oil change given that it has a certain factory defect

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, we have that:

Event A: having a factory defect.

Event B: needing an oil change.

The probability that a car has a certain factory defect is 825.

So $P(A) = 0.825$

The probability that a car has a certain factory defect and needs an oil change is 750.

So $P(A \cap B) = 0.75$

What is the probability that a car needs an oil change given that it has a certain factory defect

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.75}{0.825} = 0.9091$

90.91% probability that a car needs an oil change given that it has a certain factory defect

5 0

4 years ago

A company's profit in the first half of the year is $150,000 more than the second half of the year. If the total profit for the

natta225 [31]

Answer:

Profit for First half of the year is $450,000.

Step-by-step explanation:

Let the profit for second half of year be x

Now Given:

Profit in the first half of the year is $150,000 more than the second half of the year.

Profit in first half = $\$150,000+x$

Total profit for the year = $850,000

We know that Total profit for the year is sum of Profit in first half and Profit in second half

$150000+x+x=850000\\150000+2x=850000\\2x= 850000-150000\\2x = 600000\\\\x=\frac{600000}{2}=300000$

Profit for Second half of year = $300000

Profit for First half of the year = $150000+x = 150000+300000=\$450,000$

Hence Profit for First half of the year is $450,000.

6 0

3 years ago