Answer:
P(1.5, 3.5)
Step-by-step explanation:
We need to find the average of the x and y coordinates. We do this by adding the two values, then dividing by two:
P(x1 + x2/ 2, y1 + y2/2) = P(1 + 2/ 2, 2 + 5/ 2) = P(3/2, 7/2) = P(1.5, 3.5)
These are our coordinates!
You need to find the unit rate of 3 : 1800 first by dividing 1800 and 3
1800 ÷ 3 = 600
So this means for every 1 pound bag it covers 600 square feet. You now need to multiply 600 and 4 to see how many square feet 4 pounds cover.
600 × 4 = 2400
So each 4 pounds covers 2400 sq ft. Now you have to divide 8400 and 2400 to find how many bags of 4 pounds you need
8400 ÷ 2400= 3.5
You need 3.5 bags of 4 pounds.
Technically you would need 4 bags because you’d have to round it up.
Hope this helps you!! :)
Answer:
80 minutes or 1 h 20 minutes
Step-by-step explanation:
15-13=2
2/0.025=80
So we can conclude that it takes 80 minutes till it reaches 13 feet.
It depends on the vehicle but normally four of five
Answer:
You should make 250 quarts of Creamy Vanilla and 200 of Continental Mocha to use up all the eggs and cream.
Step-by-step explanation:
This problem can be solved by a first order equation
I am going to call x the number of quarts of Creamy Vanilla and y the number of quarts of Continental Mocha.
The problem states that each quart of Creamy Vanilla uses 2 eggs and each quart of Continental Mocha uses 1 egg. There are 700 eggs in stock, so:
2x + y = 700.
The problem also states that each quart of Creamy Vanilla uses 3 cups of cream and that each quart of Continental Mocha uses 3 cups of cream. There are 1350 cups of cream in stock, so:
3x + 3y = 1350
Now we have to solve the following system of equations
1) 2x + y = 700
2) 3x + 3y = 1350
I am going to write y as function of x in 1) and replace it in 2)
y = 700 - 2x
3x + 3(700 - 2x) = 1350
3x + 2100 - 6x = 1350
-3x = -750 *(-1)
3x = 750
x = 250
You should make 250 quarts of Creamy Vanilla
Now, replace it in 1)
y = 700 - 2x
y = 700 - 2(250)
y = 700 - 500
y = 200.
You should make 200 quarts of Continental Mocha
