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Aleksandr-060686 [28]

3 years ago

14

The Osborn family goes out to dinner, and the price of the meal is $60. The sales tax on the meal is 7%, and they also want to l

eave a 15% tip. What is the total cost of the meal?

1 answer:

siniylev [52]3 years ago

3 0

The total cost of the meal is $73.83

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If f'(x) = 3(x+5) +-, what is ffa + 2)?

lubasha [3.4K]

Answer:

-13/3

Step-by-step explanation:

Let f(x)=A

x=f'(A)

x=3(A+5)

A=(x-15)/3

f(x)=(x-15)/3

ff(2)=(2-15)/3

=-13/3

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2 years ago

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2 years ago

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A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

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2 years ago

Dovator [93]

Answer:

-4,15 -14,5 6,5

Step-by-step explanation:

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2 years ago