X quantity of first plant which cost $7
y quantity of second plant which cost $10
z quantity of third plant which cost $13
{x+y+z=15
{7x+10y+13z=150
There are 8 solutions with spending $150
Five of them are:
1x$7 + 13x$10 + 1x$13
2x$7 + 11x$10 +2x$13
3x$7 + 9x$10 +3x$13
5x$7 + 5x$10 + 5x$13
6x$7 + 3x$10 + 6x$13
Step 
<u>Find the value of MN</u>
In the right triangle MNL
Applying the Pythagorean Theorem
Solve for MN
in this problem we have
Substitute in the formula above
Step 
<u>Find the value of cos (M)</u>
we know that
In the right triangle MNL
Substitute the value of MN
therefore
<u>the answer is</u>
The value of cos(M) is 
Answer:
7 :)
Step-by-step explanation:
Answer:
11.14 brailiest please
Step-by-step explanation:
Answer:
x = 2
Step-by-step explanation:
Both equations are equal to y, so they're also equal to each other. We then set them equal to each other:
x^2 - 2x + 1 = x^2 + 2x - 7
We now do algebra to isolate x. Subtract 1 from both sides.
x^2 - 2x = x^2 + 2x - 8
Subtract 2x from both sides.
x^2 - 4x = x^2 - 8
Subtract x^2 from both sides.
-4x = -8
Divide both sides by -4.
x = 2
