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3 years ago

Evaluate expression 6+3+2?

Mathematics

2 answers:

Verdich [7]3 years ago

6 0

First you need to add 6+3. Which is 9. Then you need to add 9+2. Which is 11. Your answer is 11.

RoseWind [281]3 years ago

4 0

The correct sum would be 11

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Mona wants to run more than 60 miles this week. She ran a total of 24 miles during the first 4 days of the week. ... Line repres

andreyandreev [35.5K]

Answer: Rate > 12 miles/day

x > 12

She must run more than 12 miles each day

Mona wants to run more than 60 miles this week. She ran a total of 24 miles during the first 4 days of the week. Which number line represents the number of miles Mona must run each day if she wants to meet her goal?

answer choices

x ≥ 10

x = 12

x > 10

x > 12

Step-by-step explanation:

To complete more than 60 miles a week.

After running 24 miles during the first 4 days

We are left with (7-4) days = 3 days

And also,

(60-24) miles to complete the weekly target

> 36 miles (more than 36miles)

Therefore, the number of miles needed to cover per day in the next 3 days is given as.

Rate > distance/time

Rate > 36miles/3days

Rate > 12 miles/day

7 0

3 years ago

Write the equation of the line in Standard Form.

Phantasy [73]

Answer:

hmmm

Step-by-step explanation:

5 0

3 years ago

Solve log_x(1/32)=-5

leva [86]

Remember

$log_a(b)=c$ translates to $a^c=b$

so
$log_x(\frac{1}{32})=-5$ translates to $x^{-5}=\frac{1}{32}$
remember, if a^b=c^b when b=b, then a=c
and x^-m=1/(x^m)

hmm
$x^{-5}=\frac{1}{32}$
$\frac{1}{x^5}=\frac{1}{32}$
32=x⁵
5th root both sides
2=x
x=2

3 0

3 years ago

Plz need asap!!!!!!!!!

joja [24]

OK so if 70% of students in 8th grade have siblings and 112 8th graders have siblings, then:

0.7(total 8th graders) = 112

total 8th graders = 112/0.7

total 8th graders = 160

And since the number of 8th graders is 5/6 the size of the 7th grade class:

5/6(7th grade class) = 160

5(7th grade class) = 960

7th grade class = 192.

The correct answer is D) 192.

Hope this helps

cheers,

Brian

7 0

3 years ago

?? “solve the missing elements for each problem. use 3.14 for area

velikii [3]

Answer:

Problem 4:

Radius = 11 cm.

Circumference = 69.08 cm.

Problem 5:

Radius = 14 mm.

Circumference = 87.92 mm.

Problem 6:

Radius = 9 inches.

Circumference = 56.52 inches.

Problem 7:

Diameter = 32 ft.

Circumference = 100.48 ft.

Problem 8:

Diameter = 26 yards.

Circumference = 81.64 yards.

Problem 9:

Diameter = 12 cm.

Circumference = 37.68 cm.

Step-by-step explanation:

Problem 4:

Given:

Diameter GH = 22 cm

We need to find the radius EF and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius EF = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 22 = 11 \ cm$

Circumference = $\pi \times Diameter = 3.14 \times 22 = 69.08\ cm$

Hence Radius = 11 cm

Circumference = 69.08 cm.

Problem 5:

Given:

Diameter OP = 28 mm

We need to find the radius MN and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius MN = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 28 = 14 \ mm$

Circumference = $\pi \times Diameter = 3.14 \times 28 = 87.92\ mm$

Hence Radius = 14 mm

Circumference = 87.92 mm.

Problem 6:

Given:

Diameter EF = 18 inches

We need to find the radius CD and Circumference of the circle.

Now radius is given by half of the diameter

Also Circumference is given by π times diameter.

Radius CD = $\frac{1}{2}\times Diameter = \frac{1}{2}\times 18 = 9 \ in$

Circumference = $\pi \times Diameter = 3.14 \times 18 = 56.52\ in$

Hence Radius = 9 inches.

Circumference = 56.52 inches.

Problem 7:

Given:

Radius GH = 16 ft

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter KJ = $2 \times radius = 2 \times 16 = 32 \ ft$

Circumference = $\pi \times Diameter = 3.14 \times 32 = 100.48\ ft$

Hence Diameter = 32 ft.

Circumference = 100.48 ft.

Problem 8:

Given:

Radius LM = 13 yards

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter NO = $2 \times radius = 2 \times 13 = 26 \ yards$

Circumference = $\pi \times Diameter = 3.14 \times 26 = 81.64\ yards$

Hence Diameter = 26 yards.

Circumference = 81.64 yards.

Problem 9:

Given:

Radius NO = 6 cm

We need to find the Diameter CD and Circumference of the circle.

Now Diameter is given by twice the radius.

Also Circumference is given by π times diameter.

Diameter PQ = $2 \times radius = 2 \times 6 = 12 \ cm$

Circumference = $\pi \times Diameter = 3.14 \times 12 = 37.68\ cm$

Hence Diameter = 12 cm.

Circumference = 37.68 cm.

3 0

3 years ago