9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
Answer:$0.27
Step-by-step explanation:
20=$5.49
1=20/5.49
1=$0.2745
13 feet wide.
156/12=13
Brainliest plz
Answer:
see below
Step-by-step explanation:
m²+8m=0
Factor out an m
m(m+8) =0
Using the zero product property
m=0 m+8 =0
m =0 m=-8
Factors of the given quadratic are irrational. You could say it is
Prime
_____
roots are 3.5±√4.25 ≈ {1.438, 5.562}
