Question

The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.37 m. She sets the pendulum swinging, and her collaborators carefully count 108 complete cycles of oscillation during 209 s. What is the result?

Answer 1

Answer:

Explanation:

Length of pendulum l = 1.37 m

time period T =  time /no of oscillation

= $\frac{209}{108}$

= 1.935

Formula for time period of pendulum

$T=2\pi\sqrt{\frac{l}{g} }$

g is acceleration due to gravity , l is length of pendulum and T is time period.

Substituting the given values

$1.935=2\pi\sqrt{\frac{1.37}{g} }$

.095 = $\frac{1.37}{g}$

g = 14.42 m /s².