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3 years ago

What are the missing coefficients needed to make this equation balanced from left to right?

Physics

1 answer:

12345 [234]3 years ago

3 0

Explanation:

Since the equation is not given in this case, you can follow this explanation to balance it up.

A balanced chemical equation is one in which the law of conservation of matter is strictly obeyed.

According to the laws, we know that the total mass of the reacting substances must be equal to that of the product.

To do this, coefficients are usually assigned to chemical species.

In order to know the right coefficient one can use;

A trial by error method of inspecting and putting the appropriate coefficients in front of the formula of reactants or products.
A mathematical method in which simple equations are derived can be used.

learn more:

Balanced equation brainly.com/question/2612756

#learnwithBrainly

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3 years ago

What affect does friction have on motion

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3 years ago

A traffic light of weight 100 N is supported by two ropes that make 30-degree angle with the horizontal. What is the vertical co

alina1380 [7]

Answer:

$T_{vertical} = 50 N$

Explanation:

given,

traffic light weight = 100 N

angle at which the rope is supported = 30°

vertical component of force = ?

$2 T sin \theta= W$

$2 T sin 30^0= 100$

$T = \dfrac{100}{2 sin 30^0}$

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3 years ago

How far from Earth must a space probe be along a line toward the Sun so that the Sun's gravitational pull on the probe balances

Tatiana [17]

Answer:

258774.9441 m

Explanation:

x = Distance of probe from Earth

y = Distance of probe from Sun

Distance between Earth and Sun = $x+y=149.6\times 10^6\ m$

G = Gravitational constant

$M_s$ = Mass of Sun = $1.989\times 10^{30}$

$M_e$ = Mass of Earth = $5.972\times 10^{24}\ kg$

According to the question

$\frac{GM_sm}{x^2}=\frac{GM_em}{y^2}\\\Rightarrow \frac{M_s}{x^2}=\frac{M_e}{y^2}\\\Rightarrow x=\sqrt{\frac{M_s\times y^2}{M_e}}\\\Rightarrow x=\sqrt{\frac{1.989\times 10^{30}\times y^2}{5.972\times 10^{24}}}\\\Rightarrow x=577.10852y$

$x+y=149.6\times 10^6\\\Rightarrow 577.10852y+y=149.6\times 10^6\\\Rightarrow 578.10852y=149.6\times 10^6\\\Rightarrow y=\frac{149.6\times 10^6}{578.10852}\\\Rightarrow y=258774.9441\ m$

The probe should be 258774.9441 m from Earth

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