We have: K.E. = 1/2 mv²
Here: m = 3 Kg
v = 6 m/s
Substitute their values,
K.E. = 1/2 * 3 * 6²
K.E. = 1/2 * 3 * 36
K.E. = 54 J
In short, Your Answer would be 54 Joules
Hope this helps!
Momentum = mass x acceleration
5 x 2 = 10 kg. m/s
The height of the projectile is given by:
h = ut - 0.5at²
The height will be 0 twice, once at t = 0 and the second time at the time when the journey has been completed, or t = hang time.
0 = 7.3t - 0.5(9.81)t²
t = 1.49 seconds
Units such as kilograms (about 2.2 pounds)n which are a thousand grams,grams,centigrams (hundredths of grams), and milligrams (thousands of grams).
Answer:
<em>85.12 μAmp</em>
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Explanation:
The battery power output = 17.15 Amp-hr
If the battery is to last 23 years, we have to calculate how many hours there are in 23 years
in one year there are 24 hours x 365 day = 8760 hrs
in 23 years there are 23 x 8760 = 201480 hours
maximum current to be drawn from the battery = (17.15 Amp-hr) ÷ (201480 hours) = 85.12 x 10^-6 Amp = <em>85.12 μA</em>
