Answer:
K.E₂ = mg(h - 2R)
Explanation:
The diagram of the car at the top of the loop is given below. Considering the initial position of the car and the final position as the top of the loop. We apply law of conservation of energy:
K.E₁ + P.E₁ = K.E₂ + P.E₂
where,
K.E₁ = Initial Kinetic Energy = (1/2)mv² = (1/2)m(0 m/s)² = 0 (car initially at rest)
P.E₁ = Initial Potential Energy = mgh
K.E₂ = Final Kinetic Energy at the top of the loop = ?
P.E₂ = Final Potential Energy = mg(2R) (since, the height at top of loop is 2R)
Therefore,
0 + mgh = K.E₂ + mg(2R)
<u>K.E₂ = mg(h - 2R)</u>
Correct question:
Consider the motion of a 4.00-kg particle that moves with potential energy given by
a) Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?
b) What is the magnitude of the force on the 4.00-kg particle when it is located at x = 5.00 m?
Answer:
a) 3.33 m/s
b) 0.016 N
Explanation:
a) given:
V = 3.00 m/s
x1 = 1.00 m
x = 5.00
At x = 1.00 m
= 4J
Kinetic energy = (1/2)mv²
= 18J
Total energy will be =
4J + 18J = 22J
At x = 5
= -0.24J
Kinetic energy =
= 2Vf²
Total energy =
2Vf² - 0.024
Using conservation of energy,
Initial total energy = final total energy
22 = 2Vf² - 0.24
Vf² = (22+0.24) / 2
= 3.33 m/s
b) magnitude of force when x = 5.0m
At x = 5.0 m
= 0.016N
A
The delta indicates a difference or change. such as delta y is the change in y position
Answer:
F = 5000 [N] or 5 [kN]
Explanation:
In order to solve this problem we must take into account Newton's second law, which tells us that the sum of all forces applied on a body must be equal to the product of the mass of the body by its acceleration.
F = m*a
where:
F = force [N]
m = mass = 1000 [kg]
a = acceleration = 5 [m/s^2]
F = (1000*5)
F = 5000 [N] or 5 [kN]
In simple words, flux can be stated as the rate of flow of a fluid, radiant energy, or particles across a given area.
<u>Explanation:</u>
<u>Mutual Flux:</u>
- The magnetic lines present in among two magnets or solenoid is mutual flux.
- These are the lines in which the attraction and repulsion happens.
- The SI unit of mutual flux is the Henry
<u>Leakage Flux:</u>
- In simple words, it can be stated as the magnetic flux which does not follow the specially designed way in a magnetic circuit.
- Leakage flux in the induction motor takes spot due to current runs through the essence of the induction motor.
- The SI unit of Leakage flux is the Weber
<u>Magnetizing flux</u>
- Magnetic flux is an analysis of the entire magnetic field which moves in a given field
- In simple words can be defined as the Magnetic flux is what generates the field around a magnetic material.
- The SI unit of magnetic flux is the Weber
