Answer:
![f = 421.8 Hz](https://tex.z-dn.net/?f=f%20%3D%20421.8%20Hz)
Explanation:
When she moved a distance of 1 m from mid point she observe first destructive interference due to two speakers
so we can say that path difference of sound due to two speakers will be equal to half of the wavelength
so path difference is given as
![\Delta L = {3.5^2 + 12^2}^{0.5} - {1.5^2 + 12^2}^{0.5}](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%20%7B3.5%5E2%20%2B%2012%5E2%7D%5E%7B0.5%7D%20-%20%7B1.5%5E2%20%2B%2012%5E2%7D%5E%7B0.5%7D)
so it will be
![\Delta L = 12.5 - 12.093](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%2012.5%20-%2012.093)
![\Delta L = 0.4066](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%200.4066)
now we know that
![\frac{\lambda}{2} = 0.4066](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clambda%7D%7B2%7D%20%3D%200.4066)
![\lambda = 0.813](https://tex.z-dn.net/?f=%5Clambda%20%3D%200.813)
now frequency of sound is given as
![f = \frac{v}{\lambda}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7Bv%7D%7B%5Clambda%7D)
![f = \frac{343}{0.813}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B343%7D%7B0.813%7D)
![f = 421.8 Hz](https://tex.z-dn.net/?f=f%20%3D%20421.8%20Hz)
TLDR: It will reach a maximum when the angle between the area vector and the magnetic field vector are perpendicular to one another.
This is an example that requires you to investigate the properties that occur in electric generators; for example, hydroelectric dams produce electricity by forcing a coil to rotate in the presence of a magnetic field, generating a current.
To solve this, we need to understand the principles of electromotive forces and Lenz’ Law; changing the magnetic field conditions around anything with this potential causes an induced current in the wire that resists this change. This principle is known as Lenz’ Law, and can be described using equations that are specific to certain situations. For this, we need the two that are useful here:
e = -N•dI/dt; dI = ABcos(theta)
where “e” describes the electromotive force, “N” describes the number of loops in the coil, “dI” describes the change in magnetic flux, “dt” describes the change in time, “A” describes the area vector of the coil (this points perpendicular to the loops, intersecting it in open space), “B” describes the magnetic field vector, and theta describes the angle between the area and mag vectors.
Because the number of loops remains constant and the speed of the coils rotation isn’t up for us to decide, the only thing that can increase or decrease the emf is the change in magnetic flux, represented by ABcos(theta). The magnetic field and the size of the loop are also constant, so all we can control is the angle between the two. To generate the largest emf, we need cos(theta) to be as large as possible. To do this, we can search a graph of cos(theta) for the highest point. This occurs when theta equals 90 degrees, or a right angle. Therefore, the electromotive potential will reach a maximum when the angle between the area vector and the magnetic field vector are perpendicular to one another.
Hope this helps!
The ball can't reach the speed of 20 m/s in two seconds, unless you THROW it down from the window with a little bit of initial speed. If you just drop it, then the highest speed it can have after two seconds is 19.6 m/s .
If an object starts from rest and its speed after 2 seconds is 20 m/s, then its acceleration is 20/2 = 10 m/s^2 .
(Gravity on Earth is only 9.8 m/s^2.)
Responder:
<h3>
150 Nm
</h3><h3>
Energía potencial
</h3>
Explicación:
El tipo de energía que posee el objeto se conoce como energía potencial. <u>La energía potencial es la energía que posee un objeto, mi virtud de su posición.
</u>
Energía potencial = masa * aceleración debido a la gravedad * altura
Dado que Force = masa * aceleración debido a la gravedad
Energía potencial = Fuerza * altura
Fuerza dada = 50N y altura = 3 m
Energía potencial = 50 * 3
Energía potencial = 150 Nm
Answer:
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
Explanation:
The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.
Given are
<em> mass of the student 73 kg</em>
<em> height of water glide 11.8 m</em>
<em> work done as -5.5*10³ J</em>
Have to find speed at which the student goes down the glide.
According to<em> Law of Conservation of energy</em>,
K.E =P.E+Work Done
mv²/2=mgh +W
Rearranging the above eqn for v
v = √2(gh+W/m)
Substituting values,
V = 12.48 m/s.
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>