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torisob [31]
3 years ago
13

A piece of green jade has a mass of 23.401 g.if the sample of jade displaces 50.0 ml of water to 56.5 ml in a 100 ml graduated c

ylinder,what is the density of the jade.
Mathematics
1 answer:
OleMash [197]3 years ago
3 0

we know that

The density is equal to the formula

Density=\frac{mass}{volume}

in this problem we have

mass=23.401\ gr

<u>Find the volume of a piece of green jade</u>

Volume=56.5\ ml-50.0\ ml=6.5\ ml

Substitute the values in the formula of density

Density=\frac{23.401}{6.5}

Density=3.60\frac{gr}{ml}

therefore

<u>the answer is</u>

Density=3.60\frac{gr}{ml}

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Answer: A=351.68 cm²

Step-by-step explanation:

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weeeeeb [17]

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<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

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\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

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2 years ago
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Hope this helps!
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yaroslaw [1]

Given:

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