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3 years ago

12 pls. Dis is due tomorrow I need helppp

Mathematics

1 answer:

givi [52]3 years ago

7 0

Multiplying positive numbers always comes out positive, no matter how many there are. So you can forget about the positive ones.

Every two negative numbers in a multiplication produce a positive.
Another way to say that is: If the number of negative ones is EVEN,
the answer is positive, and if it's ODD, the answer is negative.

That monster product of eight numbers in problem #12 will be negative,
because there are an odd amount of negative factors in it.

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Whats the value of u+5v-w,if u=6, and w=9?

Vitek1552 [10]

To solve this we need only substitute values of u and w, and then calculate.

<span>u+5v-w = 6 + 5v - 9 = 5v +6 - 9 = 5v - 3</span>

3 0

3 years ago

A shipping container is in the shape of a right rectangular prism with a length of 13 feet, a width of 4.5 feet, and a height of

AnnZ [28]

Answer:

The volume of the right rectangular prism is 12* 8.5 * 4 = 408 content density is 0.25 pounds

Step-by-step explanation:

4 0

4 years ago

Which is greater 2/3 or 2/4

zheka24 [161]

2/3 = 66%
2/4 = 50%
Therefore, 2/3 is greater

4 0

3 years ago

Find the sum of the positive integers less than 200 which are not multiples of 4 and 7

taurus [48]

Answer:

$12942$ is the sum of positive integers between $1$ (inclusive) and $199$ (inclusive) that are not multiples of $4$ and not multiples $7$ .

Step-by-step explanation:

For an arithmetic series with:

$a_1$ as the first term,
$a_n$ as the last term, and
$d$ as the common difference,

there would be $\displaystyle \left(\frac{a_n - a_1}{d} + 1\right)$ terms, where as the sum would be $\displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n)$ .

Positive integers between $1$ (inclusive) and $199$ (inclusive) include:

$1,\, 2,\, \dots,\, 199$ .

The common difference of this arithmetic series is $1$ . There would be $(199 - 1) + 1 = 199$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}$ .

Similarly, positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $4$ include:

$4,\, 8,\, \dots,\, 196$ .

The common difference of this arithmetic series is $4$ . There would be $(196 - 4) / 4 + 1 = 49$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}$

Positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $7$ include:

$7,\, 14,\, \dots,\, 196$ .

The common difference of this arithmetic series is $7$ . There would be $(196 - 7) / 7 + 1 = 28$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}$

Positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $28$ (integers that are both multiples of $4$ and multiples of $7$ ) include:

$28,\, 56,\, \dots,\, 196$ .

The common difference of this arithmetic series is $28$ . There would be $(196 - 28) / 28 + 1 = 7$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}$ .

The requested sum will be equal to:

the sum of all integers from $1$ to $199$ ,
minus the sum of all integer multiples of $4$ between $1\!$ and $199\!$ , and the sum integer multiples of $7$ between $1$ and $199$ ,
plus the sum of all integer multiples of $28$ between $1$ and $199$ - these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

$19900 - 4900 - 2842 + 784 = 12942$ .

8 0

3 years ago

Part A: Billy rented a canoe at $14 for 2 hours. If he rents the same canoe for 5 hours, he has to pay a total rent of $29. Writ

zepelin [54]

Part A)

So we need the graph to pass through these points:

time = 2 and price=$14 -> (2,14)

time= 5 and price = $29 -> (5,29)

Standard form:

Ax+By = C

Let’s replace the points:

A*2+B*14=C

A*5+B*29=C

Let’s eliminate variables:

(A*2+B*14)-(A*5+B*29)=C-C

A*2+B*14-A*5-B*29=0

-3A-15B=0

-3A=15B

A=15B/-3

A=-5B

There are several numbers that verify this proportion. For example, if B=1, A=-5 (you can try others, there is not only 1 correct answer).

So we can make this equation:

-5x+y=C

Then we can calculate C using one point:

-5*2+14=C

-10+14=C

4=C

So one of the possible equations is: -5x+y=4

(Remember there are multiple correct answers for this item)

You can verify it with the other point:

-5*5+29=-25+29=4 ->OK

Part B)

Whatever you have found in Part A, you will find the same in Part B when you convert it to function notation. All you have to do is clear y:

-5x+y=4

y=4+5x

So the equation is: f(x)=4+5x

Part C)

First of all, you have to find f(0)

f(x)=4+5x

f(0) =4+5*0=4+0=0

f(0) is ALWAYS the constant not multiplied by x.

So you know it has to cross the y axes in y=4

Now let’s put 0 as y-value:

4+5x=0

5x=0-4=-4

x=-4/5

So now you know it has to cross the x axes in x=-4/5.

So you can put those intersections in the graph and you draw the line through those points. Labels: horizontal axes is x, and in this case represents time; vertical axes is y, and in this case represents price.

Remember there are other methods, too :)

5 0

3 years ago