Answer:

Step-by-step explanation:

A. Geometric
b. a curve sloping steeply upwards (exponential)
c. nth term an = a1r^(n-1)
nth term = 4(4)^(n-1)
Answer:
<em>The numbers are 4 and 6</em>
<em />
Step-by-step explanation:
Let
x------> be the first positive even integer
x+2---> be the second positive even integer
<em>we know that the solution is a positive value</em>
<em />
<u>The numbers are 4 and 6</u>
Hope this helps!
<em>stay safe</em>
<h3>
Answer: Choice D. 4x^2 + 20x + 25</h3>
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Explanation:
Perfect square trinomials are in the form (a+b)^2 = a^2+2ab+b^2
So the first and last terms must be perfect squares. The middle term is twice that of the square roots of each first and last term.
Choice D fits the description because 4x^2 = (2x)^2 is the first term, so a = 2x and 25 = 5^2 is the last term meaning b = 5. Note how 2ab = 2*2x*5 = 20x is the middle term.
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(a+b)^2 = a^2+2ab+b^2
(2x+5)^2 = (2x)^2+2*2x*5+5^2
(2x+5)^2 = 4x^2 + 20x + 25