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Alona [7]
3 years ago
7

Anyone know wat 792 divided by 5 is?

Mathematics
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

158.4 i think

Step-by-step explanation:

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To own and operate a poster printer, it costs $250 for the printer and an additional $0.20 per poster for ink. To print out post
NARA [144]

Answer:

312.5

Step-by-step explanation:

Since it is $250 plus 20 cents per poster, the equation is 0.20p+250. It is $1 per poster at store and you want to know when the cost is going to be the same so you set them equal to each other.

0.20p+250=p

250=0.80p

312.5=p

6 0
3 years ago
I am trying to find the measure of angle KRD angle KRD: 5r+42 angle: DRB: 4r+66 I don't really understand this
SSSSS [86.1K]

Based off what you have I can't solve it

7 0
3 years ago
Evan makes cards numbered 1-18 and places them in a bag. What is the probability that he will pull out an even number, replace t
lubasha [3.4K]

Answer:

1-8

Step-by-step explanation:

6 0
3 years ago
The length of the floor is 32 m longed than it’s witdth and there is greater than 200 square meters. You will cover the floor co
Vilka [71]

Answer:

Step-by-step explanation:

The area of the floor A = Length * Width

Given

A = 200 square meters

If the length of the floor is 32 m longed than it’s width then;

L = 32+W

A = LW

200 = (32+W)W

200 = 32W + W²

W²+32W-200 = 0

W = -32±√32²+800/2

W = -32±42.71/2

W =  -32+42.71/2

W = 10.71/2

W = 5.35 m

L = 32+5.35

L = 37.35m

Hence the dimension is  5.35ft by 37.35m

8 0
3 years ago
Please helpppp it has to do with P(A U B)
Katyanochek1 [597]
P(A)=0.5, P(B)=0.6, P(A\cup B)=0.8

We find the probability of intersection using the inclusion/exclusion principle:


P(A\cap B)=P(A)+P(B)-P(A\cup B)=0.3


By definition of conditional probability,


P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{0.3}{0.6}=0.5


For A and B to be independent, we must have


P(A\cap B)=P(A)\cdot P(B)

in which case we have 0.3=0.5\cdot0.6, which is true, so A and B are indeed independent.


Or, to establish independence another way, in terms of conditional probability, we must have

P(A\mid B)\cdot P(B)=P(A)\cdot P(B)\implies P(A\mid B)=P(A)


which is also true.
7 0
3 years ago
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