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2 years ago

20 POINTS! + BRAINLIEST!

Mathematics

2 answers:

lana66690 [7]2 years ago

4 0

Answer:

idk

Step-by-step explanation:

g100num [7]2 years ago

3 0

Answer:

= x^4 -x^3 -4x^2 -3

Step-by-step explanation:

f(x) = x^4 -x^2 +9

g(x) = x^3 +3x^2 +12

We want to find f-g

(f-g) (x) = x^4 -x^2 +9 - (x^3 +3x^2 +12)

Distribute the minus sign

(f-g) (x) = x^4 -x^2 +9 - x^3 -3x^2 -12

= x^4 -x^3 -4x^2 -3

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2 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

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2 years ago

What is seven million written as numeral?

timama [110]

Answer: 7,000,000

A million= six zeroes

Ones, tens, hundreds, thousands, ten-thousands, hundred-thousands, millions

Each place value represents an additional zero

3 0

2 years ago

Read 2 more answers

what is the lub and glb of the following sets, in the set of real numbe if exists E={ 0.2,0.23,0.234,0.2343,0.23434,0.23434,...}

Brums [2.3K]

Answer:

Hello,

Step-by-step explanation:

$LUB(E)=0.2=\dfrac{1}{5} \\\\GUB(E)=0.2 34 34 34 ....=0.2+\dfrac{1}{10} *0.343434....\\\\=\dfrac{1}{5} +\dfrac{1}{10} *\dfrac{34}{99} \\\\=\dfrac{198+34}{990} \\\\=\dfrac{116}{495}$

4 0

2 years ago