The interquartile range (IQR) can be found by finding the difference of the upper and lower quartiles
Answer:
The first step to solve the equation below is to first distribute the 2 to (x+7)
Step-by-step explanation:
2 (x+7) = -4x + 14
2x + 14 = -4x + 14
The answer would be one of the following in the photo below....if not do you have a picture you could show me of the possible answers?
<u>Finding x:</u>
We know that the diagonals of a rhombus bisect its angles
So, since US is a diagonal of the given rhombus:
∠RUS = ∠TUS
10x - 23 = 3x + 19 [replacing the given values of the angles]
7x - 23 = 19 [subtracting 3x from both sides]
7x = 42 [adding 23 on both sides]
x = 6 [dividing both sides by 7]
<u>Finding ∠RUT:</u>
We can see that:
∠RUT = ∠RUS + ∠TUS
<em>Since we are given the values of ∠RUS and ∠TUS:</em>
∠RUT = (10x - 23) + (3x + 19)
∠RUT = 13x - 4
<em>We know that x = 6:</em>
∠RUT = 13(6)- 4
∠RUT = 74°
We have to find the area of the floor in order to know how many square meters of flooring they need.
The area of the floor is:
42 m* (39 m)= 1,638 m^(2)
They need 1,638 m^(2) of flooring.
Hope this helps~
