Answer:
what's the question here ?
Answer:
2.5 • 10^6
Explanation:
In order for 25 • 10^6 to be written in standard form, the ‘25’ needs to be less than 10. To do that we will move the decimal one place to the left so that 25 is now 2.5; it is now a number less than 10. It should now look like 2.5 • 10^6. It is now in standard form.
The "mean" of a group of numbers is also called their "average".
To calculate the mean, add up all the numbers, then
divide the sum by the number of items on the list.
Step #1: Addum up: 3+7+2+9+4+7+3+7+5+2 = 49
Step #2: Count the number of items on the list: I count 10 .
Step #3: Divide the sum by the number of items on the list.
49 / 10 = 4.9
The mean (average) of the numbers on that list is 4.9 .
Answer:
1963.2 pounds (lbs.)
Step-by-step explanation:
Things to understand before solving:
- - <u>Normal Probability Distribution</u>
- The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by:

The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.
- - <u>Central Limit Theorem</u>
- The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц and standard deviation

As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.
This means, ц = 2000 and б = 100.
A random sample of 20 cables is chosen and tested.
This means that n = 20, 
Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.
This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So 
- By the Central Limit Theorem


<h3>Answer:</h3>
The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.