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3 years ago

Write 1 ordered pair excluding the y-intercept given the slope and y-int. of this line.

Mathematics

1 answer:

pochemuha3 years ago

7 0

Answer:

y=2/3x+2

Step-by-step explanation:

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Amelia rented a DVD and it was due to be returned on 26 November. She actually returned it to the shop on 12 December. The rental shop applies a fine of 9p for every day the DVD is overdue.

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3 years ago

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3 years ago

There are 4 cats in a street,Five more come . How many cats are in a street ?

stealth61 [152]

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3 years ago

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A player shoots a basketball from a height of 6 feet. The equation, h = -16t^2 + 25t + 6, gives the height, h , of the basketbal

noname [10]

Answer:

$\boxed {\boxed {\sf 7.5 \ feet}}$

Step-by-step explanation:

We are given this function for the height (h) after t seconds:

$h=-16t^2+25t+6$

Seconds is t and we want to find the height after 1.5 seconds. Plug 1.5 in for t.

$h= -16(1.5)^2+25(1.5)+6$

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Solve the exponent first.

(1.5)²= 1.5*1.5=2.25

$h= -16(2.25)+25(1.5)+6$

Multiply.

$h= -36+25(1.5)+6$

$h= -36+37.5+6$

Add.

$h=1.5+6=7.5$

This is already rounded to the nearest tenth, so it is the answer.

After 1.5 seconds, the basketball is at a height of 7.5 feet.

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3 years ago

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago