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Sonbull [250]
4 years ago
6

Solve -3x + 12 = x – 4 Show your work

Mathematics
2 answers:
fiasKO [112]4 years ago
7 0
X=8
-3x+12=x-4
The answer is x=8

jeka944 years ago
3 0

Answer:

Step-by-step explanation:

-3x +12 =x-4

+3x

12 = 4x -4

+4

16 = 4x

Divide by 4

4 = x

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Pls help fast, everything is in the attached file
IgorLugansk [536]

Answer:

  • \frac{20}{369}

Step-by-step explanation:

  • \frac{ 3.4:1.8 - 1 \frac{2}{3} + \frac{7}{9} }{0.918:0.51 + 0.45} =
  • \frac{\frac{34}{18}- \frac{5}{3}+\frac{7}{9} }{18 +\frac{45}{100} } =
  • \frac{\frac{17}{9}-\frac{15}{9}+\frac{7}{9}}{18+ \frac{9}{20}  }  =
  • \frac{\frac{17-15+7}{9} }{\frac{369}{20} } =
  • \frac{9}{9} } *\frac{20}{369} =
  • \frac{20}{369}

8 0
3 years ago
Sorry it’s hard to read but I need help please and thank u so much for ur help
mixer [17]
For every 1/4 metric ton it takes 1/8 hours
then multipling by 8 to make the hours =1
for every 2 metric tons it take 1 hour
so the quotient is 2 metric tons per 1 hour
8 0
3 years ago
Read 2 more answers
B. Find the balance of the account.<br> $
DiKsa [7]
What account? :| it doesn’t have an image or anything
4 0
3 years ago
Show that (x+1)(x+3)(x+5) can be written in the form ax^3+bx^2+cx+d where a,b and c are all positive integers, and d is a negati
Deffense [45]

Answer:

THE

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
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