Answer:
![sin(-\theta)=\frac{3}{4}](https://tex.z-dn.net/?f=sin%28-%5Ctheta%29%3D%5Cfrac%7B3%7D%7B4%7D)
Step-by-step explanation:
Given:
180°<θ<270° and ![sin(\theta)=-\frac{3}{4}](https://tex.z-dn.net/?f=sin%28%5Ctheta%29%3D-%5Cfrac%7B3%7D%7B4%7D)
We know for any angle
,
![sin(-\theta)=-sin(\theta)](https://tex.z-dn.net/?f=sin%28-%5Ctheta%29%3D-sin%28%5Ctheta%29)
∴![sin(-\theta)=-(-\frac{3}{4})=\frac{3}{4}](https://tex.z-dn.net/?f=sin%28-%5Ctheta%29%3D-%28-%5Cfrac%7B3%7D%7B4%7D%29%3D%5Cfrac%7B3%7D%7B4%7D)
Μ = (0×0.026) + (1×0.072) +(2×0.152) + (3×0.303) + (4×0.215) + (5×0.164) + (6×0.066)
μ = 0 + 0.072 + 0.304 + 0.909 + 0.86 + 0.82 + 0.396
μ = 3.361 ≈ 3.4
We need the value of ∑X² to work out the variance
∑X² = (0²×0.026) + (1²×0.072) + (2²×0.152) + (3²×0.303) + (4²×0.215) + (5²×0.164) + (6²×0.066)
∑X² = 0+0.072+0.608+2.727+3.44+4.1+2.376
∑X² = 13.323
Variance = ∑X² - μ²
Variance = 13.323 - (3.4)² = 1.763 ≈ 2
Standard Deviation = √Variance = √1.8 = 1.3416... ≈ 1.4
The correct answer related to the value of mean and standard deviation is the option D
<span>
An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.4 hours.</span>
Answer:
The probability of Javier volunteers for less than three a month is 25%
Step-by-step explanation:
According to the questions,
The probability of Javier to attend exactly 5 events :-
P ( x = 5 ) = 25% = ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
The probability of Javier to attend exactly 4 events :-
P ( x = 4 ) = ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
The probability of Javier to attend exactly 3 events :-
P ( x = 3 ) = ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
The probability of Javier to attend exactly 2 events :-
P ( x = 2 ) = ![\frac{3}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B20%7D)
The probability of Javier to attend exactly 1 events :-
P ( x = 1 ) = ![\frac{1}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B20%7D)
The probability of Javier to attend no events :-
P ( x = 0 ) = ![\frac{1}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B20%7D)
Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).
P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )
P ( x < 3 ) =
=
=
= 0.25 = 25 %.