The answer
<span>the true answer is A) 4x^2+52x+165=320; x = 2.5
proof:
since </span><span>they want to limit its area to 320 in^2
x must be equal 2.5, because </span>4.(2.5)^2+52(2.5)+165= 25+130+165=320;
the main rule of the area of a triangle is
A= (base x height )/2
let be b the base and h the height
so h=20- 6b
so 50= b x( 20-6b) /2, implies 100/b = 20 - 6b
if b=x, we have 100= 20x -6x² this is equivalent to 6x² - 20x = -100
so the answer is
<span>D) None of the choices are correct.
</span>
<span>the largest dimensions that can be used for the fountain are
</span>
<span>B) x^2+8x+16=800
C) x^2+16=800
</span>
proof
x^2+8x+16=x^2+8x+4², 4² is the area of the square fountain, and x^2+8x should be the remaining of the area, t<span>he total space that the fountain and sidewalk can use is 800, it is less than 800 ft^2.
</span>Use the same method for. x^2+16=800
Answer:
a) 0.1829
b) 0.6823
c) 0.0413
Step-by-step explanation:
We are given the following information:
We treat adult having little confidence in the newspaper as a success.
P(Adult have little confidence) = 62% = 0.62
Then the number of adults follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 10
a) exactly 5
0.1829 is the probability that exactly 5 out of 10 U.S.adults have very little confidence in newspapers.
b) atleast six
0.6823 is the probability that atleast 6 out of 10 U.S. adults have very little confidence in newspapers.
c) less than four
0.0413 is the probability that less than 4 out of 10 U.S. adults have very little confidence in newspapers.
Step-by-step explanation:
36. 9 + 3x
37. (t - 2) hours
38. r + s
39. 5(p + q)
neverminding the jumbled lingo, is simply asking for the equation of the tangent line at that point, it says all tangents, well, there's only one passing there.
we can simply get the derivative of f(x) and take it from there.

since now we know the slope when x = 3/2, then we can just plug that into its point-slope intercept form, along with the coordinates.
